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Question

If \(2x - \frac{1}{2x} = 5\)\(x \neq 0\) then the value of \(x^{2} + \frac{1}{16x^{2} } - 2\) is

The correct answer is

19/4

Solving Algebraic Expression Value

We are given an algebraic equation and asked to find the value of a specific algebraic expression based on this equation. The given equation is \( 2x - \frac{1}{2x} = 5 \), where \( x \neq 0 \). We need to find the value of \( x^{2} + \frac{1}{16x^{2} } - 2 \).

Step-by-Step Solution to Find the Value

To find the value of the expression \( x^{2} + \frac{1}{16x^{2} } - 2 \), we should use the given equation \( 2x - \frac{1}{2x} = 5 \) and manipulate it. Our goal is to create terms like \( x^2 \) and \( \frac{1}{16x^2} \) from the given equation.

  1. Start with the given equation:
    The initial equation provided is \( 2x - \frac{1}{2x} = 5 \).
  2. Modify the equation:
    We notice the target expression has \( x^2 \) and \( \frac{1}{16x^2} \). If we square the original equation \( 2x - \frac{1}{2x} = 5 \), we would get \( (2x)^2 = 4x^2 \) and \( (\frac{1}{2x})^2 = \frac{1}{4x^2} \). To get terms more directly related to \( x^2 \) and \( \frac{1}{16x^2} \), let's divide the entire original equation by 2:
    \( \frac{1}{2} \left( 2x - \frac{1}{2x} \right) = \frac{5}{2} \)
    This simplifies to:
    \( x - \frac{1}{4x} = \frac{5}{2} \)
  3. Square both sides of the modified equation:
    Now, squaring both sides of the equation \( x - \frac{1}{4x} = \frac{5}{2} \) will introduce the square terms we are looking for:
    \( \left( x - \frac{1}{4x} \right)^2 = \left( \frac{5}{2} \right)^2 \)
  4. Expand and simplify the squared equation:
    Using the algebraic identity for the square of a difference, \( (a-b)^2 = a^2 - 2ab + b^2 \), with \( a=x \) and \( b=\frac{1}{4x} \):
    \( x^2 - 2(x)\left(\frac{1}{4x}\right) + \left(\frac{1}{4x}\right)^2 = \frac{5^2}{2^2} \)
    Simplify the terms:
    \( x^2 - 2 \cdot \frac{x}{4x} + \frac{1^2}{(4x)^2} = \frac{25}{4} \)
    \( x^2 - \frac{2}{4} + \frac{1}{16x^2} = \frac{25}{4} \)
    \( x^2 - \frac{1}{2} + \frac{1}{16x^2} = \frac{25}{4} \)
  5. Rearrange to find the value of \( x^2 + \frac{1}{16x^2} \):
    Let's isolate the terms \( x^2 + \frac{1}{16x^2} \) by moving the constant term \( -\frac{1}{2} \) to the right side of the equation:
    \( x^2 + \frac{1}{16x^2} = \frac{25}{4} + \frac{1}{2} \)
    To add the fractions on the right side, find a common denominator, which is 4:
    \( x^2 + \frac{1}{16x^2} = \frac{25}{4} + \frac{1 \cdot 2}{2 \cdot 2} \)
    \( x^2 + \frac{1}{16x^2} = \frac{25}{4} + \frac{2}{4} \)
    Combine the fractions:
    \( x^2 + \frac{1}{16x^2} = \frac{25 + 2}{4} \)
    \( x^2 + \frac{1}{16x^2} = \frac{27}{4} \)
  6. Substitute the value into the target expression:
    The expression we were asked to evaluate is \( x^{2} + \frac{1}{16x^{2} } - 2 \). We have just found that \( x^{2} + \frac{1}{16x^{2} } = \frac{27}{4} \). Substitute this value into the expression:
    Value \( = \left( x^{2} + \frac{1}{16x^{2} } \right) - 2 \)
    Value \( = \frac{27}{4} - 2 \)
    To perform the subtraction, write 2 as a fraction with denominator 4:
    Value \( = \frac{27}{4} - \frac{2 \cdot 4}{1 \cdot 4} \)
    Value \( = \frac{27}{4} - \frac{8}{4} \)
    Perform the subtraction of the fractions:
    Value \( = \frac{27 - 8}{4} \)
    Value \( = \frac{19}{4} \)

Final Result

Based on the steps above, the value of the expression \( x^{2} + \frac{1}{16x^{2} } - 2 \) is \( \frac{19}{4} \).

Revision Table: Key Concepts in Algebraic Manipulation

This problem involves manipulating equations and using algebraic identities.

ConceptDescriptionRelevance to Problem
Equation ManipulationPerforming the same operation (addition, subtraction, multiplication, division, squaring, etc.) on both sides of an equation to maintain equality while changing its form.Dividing the initial equation by 2 and squaring the resulting equation were key manipulations.
Algebraic IdentitiesFormulas that are true for all values of the variables involved (e.g., \( (a-b)^2 = a^2 - 2ab + b^2 \)).Used the square of a difference identity to expand \( (x - \frac{1}{4x})^2 \).
Fraction ArithmeticRules for adding, subtracting, multiplying, and dividing fractions. Used for combining terms like \( \frac{25}{4} + \frac{1}{2} \) and \( \frac{27}{4} - 2 \).


 

Additional Information: Solving Problems with Related Expressions

When you are given an equation involving a variable and asked to find the value of an expression involving related terms (like squares of the variable or its reciprocal), consider these approaches:

  • Look for ways to square (or cube, etc.) the given equation or a modified version of it to generate the required terms.
  • Use algebraic identities like \( (a+b)^2 \), \( (a-b)^2 \), \( a^2-b^2 \), etc., to simplify or transform expressions.
  • Sometimes you might need to find the value of intermediate expressions first (like finding \( x^2 + \frac{1}{16x^2} \) in this case) before substituting into the final expression.
  • Always check the constraints on the variables (like \( x \neq 0 \)) to ensure expressions are defined.
  • Practice recognizing patterns between the given equation and the target expression to choose the right manipulation strategy.
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Important Questions from Algebric Equations

  1. If m + n = 24, then (m - 16)³ + (n - 8)³ is ____.

  2. For the following equations, what are the values of a and b to have infinitely many solutions?

    ax + by = 2

    3x - (5 - 2ay) = 6

  3. If \(x + \frac{1}{x} = 2\), then the value of \(x^{99} + \frac{1}{ x^{99} } - 2\) 

  4. What positive value of X satisfies the equation $\frac{X}{147} = \frac{48}{X}$?
  5. The cost of 8 pens and 10 pencils is ₹132. If the cost of a pen decreases by ₹2 and the cost of a pencil increases by ₹7, then the cost of 17 pens and 6 pencils is ₹136. What is the original cost of 12 pens and 9 pencils?

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