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Question

If $(1.001)^{1259} = 3.52$ and $(1.001)^{2062} = 7.85$, then $(1.001)^{3321} =$

The correct answer is
27.64

Solving the Exponential Equation $(1.001)^{3321}$

The problem asks us to find the value of $(1.001)^{3321}$ given two other values involving the same base raised to different powers.

Key Exponent Property

We can use the exponent rule: $a^{m+n} = a^m \times a^n$.

Applying the Property

  1. Observe the relationship between the exponents: $1259 + 2062 = 3321$.

  2. Therefore, we can rewrite $(1.001)^{3321}$ using the exponent rule:

    $ (1.001)^{3321} = (1.001)^{1259 + 2062} = (1.001)^{1259} \times (1.001)^{2062} $
  3. Substitute the given values into the equation:

    $ (1.001)^{3321} = 3.52 \times 7.85 $
  4. Perform the multiplication:

    $ 3.52 \times 7.85 = 27.632 $
  5. The calculated value $27.632$ is approximately equal to the option $27.64$.

Final Answer Derivation

Based on the calculation using the exponent property $a^{m+n} = a^m \times a^n$, the value of $(1.001)^{3321}$ is found by multiplying the given values $(1.001)^{1259} = 3.52$ and $(1.001)^{2062} = 7.85$. The result is $3.52 \times 7.85 = 27.632$, which matches option 4.

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Important Questions from Numerical Reasoning

  1. Among 150 faculty members in an institute, 55 are connected with each other through Facebook and 85 are connected through WhatsApp. 30 faculty members do not have Facebook or WhatsApp accounts. The number of faculty members connected only through Facebook accounts is ______________.

  2. X is 1 km northeast of Y. Y is 1 km southeast of Z. W is 1 km west of Z. P is 1 km south of W. Q is 1 km east of P. What is the distance between X and Q in km?

  3. Two numbers are, respectively, 28% and 25% less than a third number. What percent is the first number of the second number?
  4. A dealer sold three-forth (3/4th) of his articles at a gain of 20% and the remaining articles at the cost price. Find the gain earned by him in the whole transaction.

  5. 78, 65, 82, 69, 86, ?

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