Identical balls are tightly arranged in the shape of an equilateral triangle with each side containing n balls. How many balls are there in the arrangement?
n(n + 1) / 2
The problem asks us to find the total number of identical balls arranged tightly in the shape of an equilateral triangle, where each side contains 'n' balls.
Let's visualize the arrangement for small values of 'n':
We can see a pattern here. The number of balls in each row, starting from the top row, is 1, 2, 3, ..., up to n balls in the bottom row.
The total number of balls in the arrangement is the sum of the number of balls in each row.
Total balls = 1 + 2 + 3 + ... + n
This is the sum of the first 'n' natural numbers. The formula for the sum of the first 'k' natural numbers is given by $\frac{k(k+1)}{2}$.
In this case, the total number of balls is the sum of the first 'n' natural numbers, so we use the formula with 'k' replaced by 'n'.
Total number of balls = $\frac{n(n+1)}{2}$
Comparing this with the given options, we find that this formula matches option 2.
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