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Question

How many gametes will be formed in the pea plant having genotype RrTT?

The correct answer is

(b) Two

Understanding Gamete Formation in Pea Plants

Gamete formation is a crucial process in sexual reproduction where specialized haploid cells (gametes) are produced from diploid cells through meiosis. The genetic makeup of an organism, its genotype, determines the types of alleles that can be passed down to the gametes.

The question asks about the number of gametes formed by a pea plant with the genotype RrTT. This genotype involves two different genes. One gene controls a trait represented by alleles R and r (heterozygous), and the other gene controls a trait represented by alleles T and T (homozygous).

Analyzing the Genotype RrTT

Let's break down the genotype RrTT gene by gene:

  • Gene 1 (Alleles Rr): This gene is heterozygous, meaning the plant carries two different alleles (R and r) for this trait.
  • Gene 2 (Alleles TT): This gene is homozygous, meaning the plant carries two identical alleles (T and T) for this trait.

Allele Segregation During Meiosis

During meiosis, the alleles for each gene segregate, and only one allele from each gene pair goes into a gamete. This principle is part of Mendel's Law of Segregation and Law of Independent Assortment (though for two genes, Independent Assortment is more relevant for understanding combinations).

  • For the Rr gene, the possible alleles in a gamete are R or r.
  • For the TT gene, the possible allele in a gamete is always T.

Combining Alleles for Gamete Types

To find the types of gametes formed, we combine one possible allele from the first gene with one possible allele from the second gene. We can visualize this using a simple method:

Possible alleles from Rr: R, r

Possible alleles from TT: T

Combinations:

  • Combine R with T: RT
  • Combine r with T: rT

The unique types of gametes produced by a pea plant with genotype RrTT are RT and rT.

Counting the Number of Gametes

By examining the possible combinations, we find there are exactly two distinct types of gametes produced:

  1. RT
  2. rT

Therefore, the plant will form two types of gametes.

Gene Alleles in Genotype Possible Alleles in Gamete
1 Rr R or r
2 TT T

Possible Gamete Combinations Gamete Type
Allele from Rr + Allele from TT
R + T RT
r + T rT

Conclusion on Gamete Formation

A pea plant with genotype RrTT produces two types of gametes: RT and rT. The number of different types of gametes that can be formed by an organism with a given genotype can also be calculated using the formula $\text{Number of gametes} = 2^n$, where 'n' is the number of heterozygous gene pairs in the genotype. In RrTT, only Rr is heterozygous (n=1). So, $2^1 = 2$ types of gametes.

Revision Table: Key Genetics Terms

Term Definition Relevance to Gamete Formation
Genotype The genetic makeup of an organism. Determines the alleles present for gamete formation.
Allele Different forms of a gene. Alleles segregate into different gametes.
Heterozygous Having two different alleles for a gene (e.g., Rr). Each allele can potentially go into a separate gamete type.
Homozygous Having two identical alleles for a gene (e.g., TT). Only one type of allele goes into gametes from this gene.
Gamete A haploid reproductive cell (sperm or egg). Formed by meiosis and carries one allele for each gene.
Meiosis Cell division that produces haploid gametes from a diploid cell. Process where alleles segregate and assort.

Additional Information: Predicting Gamete Types

The formula $2^n$ is a quick way to determine the number of unique gamete types based on heterozygosity. Let's look at a few more examples to solidify understanding of gamete formation:

  • Genotype AAbb: Only homozygous genes (n=0). Number of gametes = $2^0 = 1$. Gamete type: Ab.
  • Genotype AaBb: Two heterozygous genes (n=2). Number of gametes = $2^2 = 4$. Gamete types: AB, Ab, aB, ab.
  • Genotype AABbCc: Two heterozygous genes (Bb and Cc, n=2). Number of gametes = $2^2 = 4$. Gamete types: ABC, ABc, aBC, aBc. (Note: A is always present from AA). Let's re-evaluate this example carefully. From AA, only A is possible. From Bb, B or b. From Cc, C or c. Combinations: ABC, AbC, ABc, Abc. Wait, this depends on how genes are written. If AABbCc has three genes, AA, Bb, Cc. n=2 for Bb and Cc. So 2 types from Bb (B, b) and 2 from Cc (C, c). From AA, only A. Combinations: A with (B or b) with (C or c). This yields ABC, ABc, AbC, Abc. Yes, 4 types. The $2^n$ formula applies to the number of heterozygous loci. For AABbCc, loci 2 and 3 are heterozygous (n=2). So $2^2 = 4$ gamete types.
  • Genotype RrTtUu: Three heterozygous genes (n=3). Number of gametes = $2^3 = 8$. Gamete types: RTU, RTu, RtU, Rtu, rTU, rTu, rtU, rtu.

This method helps predict the diversity of gametes an organism can produce, which is fundamental to understanding genetic inheritance patterns like those observed by Mendel in pea plants.

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Important Questions from Heredity and Variation

  1. Down’s syndrome is caused by:

  2. The probability of having a haemophilia carrier daughter by a haemophilia carrier mother and a normal father is:

  3. Which of the following statements are correct about Thalassemia?

    A. In β-Thalassemia, production of β-globin chain is affected, and in α-Thalassemia, production of α-globin chain is affected.

    B. α-Thalassemia is controlled by two closely linked genes HBA1 and HBA2.

    C. The genes HBA1 and HBA2 are located on chromosome 11 of each parent.

    D. β-Thalassemia is controlled by a single gene HBB.

    Choose the correct answer from the options given below:

  4. Match List-I with List-II:

    List-IList-II
    (A) Phenylketonuria(I) Incomplete dominance
    (B) Haemophilia(II) 9:3:3:1
    (C) Snapdragon(III) Pleiotropy
    (D) Dihybrid cross(IV) Sex-linked 

    Choose the correct answer from the options given below:

  5. Chromosomes in meiocytes of butterflies are:

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