The question asks about comparing the weight of an object on the Moon with its weight on Earth. To answer this, let's first understand the difference in gravitational forces on the Moon and Earth.

Weight is the force exerted by gravity on an object. It is calculated using the formula:

\(W = mg\)

where:

• \(W\) = weight of the object
• \(m\) = mass of the object
• \(g\) = acceleration due to gravity

On Earth, the acceleration due to gravity \((g_{earth})\) is approximately \(9.8 \, m/s^2\). However, on the Moon, the acceleration due to gravity \((g_{moon})\) is about \(1.63 \, m/s^2\).

To compare the weights:

1. The weight on the Moon can be expressed as:

\(W_{moon} = mg_{moon}\)

2. The weight on Earth can be expressed as:

\(W_{earth} = mg_{earth}\)

3. To find the relationship between \(W_{moon}\) and \(W_{earth}\), divide the weight on the Moon by the weight on Earth:

\(\frac{W_{moon}}{W_{earth}} = \frac{mg_{moon}}{mg_{earth}} = \frac{g_{moon}}{g_{earth}}\)

4. Substitute the known values:

\(\frac{g_{moon}}{g_{earth}} = \frac{1.63}{9.8} \approx \frac{1}{6}\)

Therefore, the weight of an object on the Moon is approximately one-sixth of its weight on Earth. This leads to the conclusion:

Correct Answer: It is one-sixth of its weight on Earth.

This understanding is crucial for various applications, including space missions and understanding gravitational effects.