Hema’s age is 5 years more than twice of Hari’s age. Suresh’s age is 13 years less than 10 times Hari’s age. If Suresh is 3 times as old as Hema, how old is Hema?
19
This problem involves finding the ages of three individuals: Hema, Hari, and Suresh, based on several relationships between their ages. We will use algebraic equations to represent these relationships and then solve them step-by-step to find Hema's age.
To make the problem easier to solve, let's assign variables to each person's age:
We are given three pieces of information that can be translated into linear equations:
| Relationship Description | Equation |
|---|---|
| Hema’s age is 5 years more than twice of Hari’s age. | \( E = 2H + 5 \quad \text{(Equation 1)} \) |
| Suresh’s age is 13 years less than 10 times Hari’s age. | \( S = 10H - 13 \quad \text{(Equation 2)} \) |
| Suresh is 3 times as old as Hema. | \( S = 3E \quad \text{(Equation 3)} \) |
Our goal is to find Hema's age (\(E\)). We can solve this system of equations by substitution.
Let's check if all conditions are met with the calculated ages:
1. Hema's age (19) is 5 years more than twice Hari's age (7):
\(2 \times 7 + 5 = 14 + 5 = 19\). This statement holds true.
2. Suresh's age (57) is 13 years less than 10 times Hari's age (7):
\(10 \times 7 - 13 = 70 - 13 = 57\). This statement holds true.
3. Suresh's age (57) is 3 times as old as Hema's age (19):
\(3 \times 19 = 57\). This statement holds true.
All conditions are satisfied, confirming Hema's age is 19.
Based on the calculations, Hema's age is 19 years.
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