The question asks about the factors that influence the half-life of a radioactive material during radioactive decay. Let's break down what half-life means and how it's determined.
Half-life (often denoted as $t_{1/2}$) is the time required for a radioactive substance to decay to half of its initial amount. It's a fundamental property of a specific radioactive isotope.
Radioactive decay is a first-order process. This means the rate of decay is directly proportional to the number of radioactive nuclei present at that time. Mathematically, this can be represented as:
$ \frac{dN}{dt} = -kN $
Where:
By integrating the rate equation, we get the integrated rate law for first-order reactions:
$ N_t = N_0 e^{-kt} $
Where:
The half-life ($t_{1/2}$) is the time when $N_t = \frac{N_0}{2}$. Substituting this into the integrated rate law:
$ \frac{N_0}{2} = N_0 e^{-kt_{1/2}} $
Divide both sides by $N_0$:
$ \frac{1}{2} = e^{-kt_{1/2}} $
Take the natural logarithm of both sides:
$ \ln\left(\frac{1}{2}\right) = -kt_{1/2} $
$ -\ln(2) = -kt_{1/2} $
Solving for $t_{1/2}$:
$ t_{1/2} = \frac{\ln(2)}{k} $
From the derived formula, $ t_{1/2} = \frac{\ln(2)}{k} $, we can see:
Based on our analysis:
Therefore, the half-life of a radioactive material during radioactive decay is independent of the initial concentration and inversely proportional to the decay constant.
| List-I | List-II |
| Electronic Configuration | First Ionisation energy (kJ mol$^{-1}$) |
| (A). ns$^2$ | (I). 2100 |
| (B). ns$^2$np$^1$ | (II). 1400 |
| (C). ns$^2$np$^3$ | (III). 800 |
| (D). ns$^2$np$^6$ | (IV). 900 |
| List-I | List-II |
| Spectroscopy | Property |
| (A). Raman | (I). Polarizability |
| (B). FTIR | (II). Dipole Moment |
| (C). UV-Visible | (III). Absorbance |
| (D). NMR | (IV). Spin |