∇ × H = J is differential form of
Ampere’s circuital law
The question asks to identify the fundamental law of electromagnetism represented by the differential equation $\nabla \times H = J$. This equation involves the curl operator ($\nabla \times$), the magnetic field intensity ($H$), and the current density ($J$). Understanding what each term means and how it relates to the behavior of electromagnetic fields is key to solving this.
So, the equation $\nabla \times H = J$ mathematically states that the curl of the magnetic field intensity at any point is equal to the current density at that point. In simpler terms, electric currents are the source of magnetic fields that swirl around them.
Let's look at the given options and their differential forms:
Comparing the given equation $\nabla \times H = J$ with the differential forms of the options, it directly matches the differential form of Ampere's circuital law (static case).
| Law | Differential Form | Description |
|---|---|---|
| Gauss's Law (Electricity) | $\nabla \cdot D = \rho_v$ | Sources of electric displacement are free charges. |
| Gauss's Law (Magnetism) | $\nabla \cdot B = 0$ | There are no magnetic monopoles (sources of magnetic flux are non-existent). |
| Faraday's Law of Induction | $\nabla \times E = - \frac{\partial B}{\partial t}$ | A changing magnetic field creates an electric field. |
| Ampere's Circuital Law (Static) | $\nabla \times H = J$ | Steady currents are sources of magnetic fields that curl around them. |
| Ampere-Maxwell Law (Time-Varying) | $\nabla \times H = J + \frac{\partial D}{\partial t}$ | Both conduction current and changing electric fields create magnetic fields. |
Based on the differential forms of the fundamental laws, the equation $\nabla \times H = J$ is the differential form of Ampere’s circuital law, specifically in the static case or when the displacement current term is ignored.
| Law | Integral Form | Differential Form |
|---|---|---|
| Gauss's Law (Electricity) | $\oint_S D \cdot dS = \int_V \rho_v dV$ | $\nabla \cdot D = \rho_v$ |
| Gauss's Law (Magnetism) | $\oint_S B \cdot dS = 0$ | $\nabla \cdot B = 0$ |
| Faraday's Law | $\oint_L E \cdot dl = - \int_S \frac{\partial B}{\partial t} \cdot dS$ | $\nabla \times E = - \frac{\partial B}{\partial t}$ |
| Ampere-Maxwell Law | $\oint_L H \cdot dl = \int_S (J + \frac{\partial D}{\partial t}) \cdot dS$ | $\nabla \times H = J + \frac{\partial D}{\partial t}$ |
Note that the equation given in the question, $\nabla \times H = J$, corresponds to the Ampere-Maxwell law when the time-varying electric displacement term ($\frac{\partial D}{\partial t}$) is zero, which is the case for static or steady currents.
Vector calculus is essential for understanding the differential forms of electromagnetic laws. The operators used are gradient, divergence, and curl.
These operators allow us to express the fundamental laws of electromagnetism as differential equations, providing a localized description of how fields behave at every point in space.
Maxwell's divergence equation for the magnetic field is given by _______.
If flux density is represented by 'B' and magnetic field is represented by 'H' in a magnetic circuit, then what will be the energy density in the magnetic field?
Maxwell's third equation is derived from _______.
Which law is represented by the given expression?
\(\int B.dl = \mu_oi_c+\mu_0\epsilon_0 \frac{d \Phi_E}{dt}\)
"Time-varying magnetic field will always produce an electric field".
The given statement is true for: