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Question

Given total cost function $C = 5Q^2 + 20Q + 5$, at price = ₹ 5 marginal cost is

The correct answer is
70

Calculating Marginal Cost from Total Cost Function

The question provides the total cost function and asks for the marginal cost (MC) at a specific price. We first need to find the marginal cost function.

Step 1: Find the Marginal Cost (MC) Function

Marginal Cost is the derivative of the Total Cost (C) function with respect to Quantity (Q).

Given Total Cost function: $C = 5Q^2 + 20Q + 5$

Differentiate C with respect to Q to find MC: $MC = \frac{dC}{dQ} = \frac{d}{dQ}(5Q^2 + 20Q + 5)$ $MC = 10Q + 20$

Step 2: Determine the Quantity (Q) for MC Calculation

The question states the price is ₹ 5. In microeconomics, firms typically produce where Price (P) equals Marginal Cost (MC). However, the derived MC function starts at ₹ 20 (for $Q > 0$) and increases. A price of ₹ 5 would imply zero production, which contradicts the provided options.

Given the options, especially ₹ 70, let's check the quantity (Q) that yields MC = ₹ 70:

Setting $MC = 70$: $70 = 10Q + 20$ $10Q = 70 - 20$ $10Q = 50$ $Q = 5$

This suggests the question implicitly relates to the scenario where the quantity produced is Q=5, despite the potentially misleading price information.

Step 3: Calculate Marginal Cost at Q=5

Substitute Q=5 into the marginal cost function:

$MC = 10(5) + 20$ $MC = 50 + 20$ $MC = 70$

Therefore, the marginal cost is ₹ 70.

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Important Questions from Applications of Derivatives

  1. The function is decreasing on :

  2. The function attains local minimum value at :

  3. What is the maximum value of y?

  4. What is the maximum value of xy ?

  5. Consider the following statements:

    1. \({\rm{y}} = \frac{{{{\rm{e}}^{\rm{x}}} + {{\rm{e}}^{ - {\rm{x}}}}}}{2}\) is an increasing function on [0, ∞).

    2. \({\rm{y}} = \frac{{{{\rm{e}}^{\rm{x}}} - {{\rm{e}}^{ - {\rm{x}}}}}}{2}\)  is an increasing function on (-∞, ∞).

    Which of the above statements is/are correct?

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