C Expression Overview

The question asks to evaluate a C language expression: $x * y < i + j || k$.

Initial variable values are:

• $i = 0$
• $j = 1$
• $k = -1$
• $x = 0.5$
• $y = 0.0$

Evaluation Breakdown

We need to follow C's operator precedence rules:

1. Multiplication ($*$) and Addition ($+$) have higher precedence than the Relational operator ($<$).
2. The Relational operator ($<$) has higher precedence than the Logical OR operator ($||$).

Let's evaluate step-by-step:

• Calculate $x * y$: $0.5 \times 0.0 = 0.0$.
• Calculate $i + j$: $0 + 1 = 1$.
• Evaluate the comparison $x * y < i + j$: $0.0 < 1$. This evaluates to $true$. In C, $true$ is often represented numerically as $1$.

Logical OR Operation

Now, evaluate the logical OR operation: $(result of comparison) || k$.

• The result of the comparison is $1$ (true).
• The value of $k$ is $-1$. In a logical context in C, any non-zero value is considered $true$.
• Evaluate $1 || -1$. Since the left operand ($1$) is $true$, the logical OR ($||$) operator short-circuits and does not need to evaluate the right operand. The result is $true$.

Final C Language Output

The expression evaluates to $true$. In C, when a boolean result is expected or implicitly converted to an integer type, $true$ is represented as $1$.

Therefore, the output of the expression is $1$.