Given a fair six-faced dice where the faces are labelled ‘1’, ‘2’, ‘3’, ‘4’, ‘5’, and ‘6’, what is the probability of getting a ‘1’ on the first roll of the dice and a ‘4’ on the second roll?
\(\frac{1}{36}\)
The rolls are independent. Each specified face has probability 1/6, so the required probability is \((1/6)(1/6)=1/36\).
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