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Question

Given a fair six-faced dice where the faces are labelled ‘1’, ‘2’, ‘3’, ‘4’, ‘5’, and ‘6’, what is the probability of getting a ‘1’ on the first roll of the dice and a ‘4’ on the second roll?

The correct answer is

\(\frac{1}{36}\)

The rolls are independent. Each specified face has probability 1/6, so the required probability is \((1/6)(1/6)=1/36\).

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Important Questions from Types of Probability

  1. If f(x) is a probability density on the real line, then which of the following is NOT a valid probability density?

  2. The probability of student A passing an exam is 2/7 and that of B passing is 5/7. If these probabilities are independent, what is the probability that only B passes the examination

  3. A die is tossed three times, What is the probability of getting an odd number at least once ?

  4. There are two containers, with one containing 4 Red and 3 Green balls and the other containing 3 Blue and 4 Green balls. One ball is drawn at random from each container. The probability that one of the balls is Red and the other is Blue will be
  5. An event has 4 possible outcomes with probabilities 1/2, 1/4, 1/8, 1/16. What will be the rate of information if there are approximately 24 outcomes/second possible?

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