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Question

Given (9 inches) ½ = (0.25 yards) ½, which one of the following statements is TRUE?

The correct answer is

9 inches = 0.25 yards

Inches and Yards: Understanding the Given Equation

The problem presents a mathematical equation involving two different units of measurement: inches and yards. Our task is to analyze this equation and identify which of the provided statements is mathematically true based on the initial relationship.

The given equation is:

$(9 \text{ inches})^{\frac{1}{2}} = (0.25 \text{ yards})^{\frac{1}{2}}$

In simpler terms, the expression $(\text{value})^{\frac{1}{2}}$ denotes the square root of that value. So, the equation can be read as the square root of 9 inches is equal to the square root of 0.25 yards.

Equation Simplification: Finding the True Statement

To convert the equation into a more straightforward form and find an equivalent true statement, we need to eliminate the square root from both sides. The operation that undoes a square root is squaring. Therefore, we will square both sides of the given equation.

Let's follow these steps to simplify the equation:

  • Step 1: Start with the original equation.
    $(9 \text{ inches})^{\frac{1}{2}} = (0.25 \text{ yards})^{\frac{1}{2}}$
  • Step 2: Square both sides of the equation to remove the fractional exponent.
    When you square a term with an exponent of $\frac{1}{2}$, the exponents multiply: $(\text{value}^{\frac{1}{2}})^2 = \text{value}^{(\frac{1}{2} \times 2)} = \text{value}^1 = \text{value}$.
    So, applying this to both sides:
    $((9 \text{ inches})^{\frac{1}{2}})^2 = ((0.25 \text{ yards})^{\frac{1}{2}})^2$
  • Step 3: Perform the squaring operation.
    This simplifies the equation to:
    $9 \text{ inches} = 0.25 \text{ yards}$

This simplified equation, $9 \text{ inches} = 0.25 \text{ yards}$, represents a true statement derived directly from the given condition.

Options Analysis: Identifying the Correct Statement

Now, we will compare our derived true statement, $9 \text{ inches} = 0.25 \text{ yards}$, with each of the provided options to determine which one is correct.

Option Statement Verification Against $9 \text{ inches} = 0.25 \text{ yards}$
1 $3 \text{ inches} = 0.15 \text{ yards}$ If $9 \text{ inches} = 0.25 \text{ yards}$ is true, then taking the square root of both sides gives $\sqrt{9} \text{ inches} = \sqrt{0.25} \text{ yards}$, which simplifies to $3 \text{ inches} = 0.5 \text{ yards}$. Since $0.15 \neq 0.5$, this option is FALSE.
2 $9 \text{ inches} = 1.5 \text{ yards}$ Our derived true statement is $9 \text{ inches} = 0.25 \text{ yards}$. Since $1.5 \neq 0.25$, this option is FALSE.
3 $9 \text{ inches} = 0.25 \text{ yards}$ This statement is identical to the equation we derived by squaring both sides of the original given equation. Therefore, this option is TRUE.
4 $81 \text{ inches} = 0.0625 \text{ yards}$ If $9 \text{ inches} = 0.25 \text{ yards}$ is true, then squaring both sides (including units) would result in $(9 \text{ inches})^2 = (0.25 \text{ yards})^2$, which simplifies to $81 \text{ (inches)}^2 = 0.0625 \text{ (yards)}^2$. However, the option states $81 \text{ inches} = 0.0625 \text{ yards}$ (without squared units). As a direct linear equivalence, this statement is FALSE.

True Statement: Final Conclusion

After carefully simplifying the initial equation and evaluating each of the provided options, it is clear that the statement "$9 \text{ inches} = 0.25 \text{ yards}$" is the only one that holds true. It is a direct mathematical consequence of the given relationship.

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Important Questions from Numerical Reasoning

  1. a, b, c are real numbers. The quadratic equation ax2 – bx + c = 0 has equal roots, which is β, then

  2. S, M, E and F are working in shifts in a team to finish a project. M works with twice the efficiency of others but for half as many days as E worked. S and M have 6 hour shifts in a day, whereas E and F have 12 hours shifts. What is the ratio of contribution of M to contribution of E in the project?

  3. If x>y>1, which of the following must be true?

    (i) In x > In y

    (ii) ex > ey

    (iii) y2 > x2

    (iv) cos x > cos y
  4. Michael lives 10 km away from where I live. Ahmed lives 5 km away and Susan lives 7 km away from where I live. Arun is farther away than Ahmed but closer than Susan from where I live. From the information provided here, what is one possible distance (in km) at which I live from Arun’s place?

  5. If IMHO = JNIP; IDK = JEL; and SO = TP, then IDC = ____.

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