In truss systems, members carry either compressive or tensile forces. The design considerations for these forces differ significantly.
Compressive members are pushed together. Their primary failure risk is buckling – a sudden sideways bending under load, especially in slender members. Resisting buckling requires greater stiffness and stability.
Tensile members are pulled apart. They fail primarily through yielding (permanent stretching) or rupture (breaking) when the stress exceeds the material's capacity. They are generally less susceptible to instability failures like buckling compared to compressive members.
To prevent buckling, compressive members in a truss need a larger cross-sectional area and often greater thickness than tensile members carrying similar loads. This increased size provides the necessary resistance to bending instability. Tensile members, lacking the buckling risk, can often be made thinner while still possessing adequate strength to avoid yielding or rupture.
Therefore, the statement that compressive parts are generally thicker than tensile parts in a truss system is factually correct due to the different failure modes they are designed to withstand.
The correct option is TRUE.
If a structure has a total of 10 joints, then what should be the minimum no. of joints in which equilibrium equations should be concurrently satisfied for stability?
The truss in known as a Plane truss since all the members lie in:
For analyzing the pin jointed frames by the method of joints, the number of equations of static equilibrium available is:
Among the following, which method is "NOT" used for anlaysing Truss.
Which of the following in not the assumption made in the analysis of trusses?