Gauge length of steel specimen as per codal provision is: Where d : larger dimension of the specimen; A 0cross sectional area of the specimen
The gauge length is a critical parameter in tensile testing of materials like steel. It is the initial length of the portion of the specimen over which elongation is measured during the test. This length is standardized by various codes and standards to ensure consistency and comparability of results obtained from different tests and laboratories.
Different standards and specimen types may specify gauge length in relation to the specimen's diameter or cross-sectional area. For many standard tensile test specimens, particularly those with circular or square cross-sections, the gauge length is related to the initial cross-sectional area \((A_0)\) of the specimen.
According to common codal provisions, the standard gauge length \((L_0)\) for a tensile specimen is often related to its initial cross-sectional area \((A_0)\) by the formula:
This specific formula arises from the relationship \(L_0 = 5d\) which is a standard proportion for many cylindrical specimens, where \(d\) is the diameter. For a circular specimen, \(A_0 = \frac{\pi d^2}{4}\). From this, \(d = \sqrt{\frac{4A_0}{\pi}}\). Substituting this into \(L_0 = 5d\) gives \(L_0 = 5 \times \sqrt{\frac{4A_0}{\pi}} = 5 \times 2 \sqrt{\frac{A_0}{\pi}} = 10 \sqrt{\frac{A_0}{\pi}}\). Calculating \(10/\sqrt{\pi}\) gives approximately \(10 / 1.772 \approx 5.64\), which is rounded to \(5.65\).
Let's examine the provided options:
5d: This is a common way to specify gauge length for cylindrical specimens based on diameter \(d\), but the question and another option involve the area \(A_0\). While related, \(5d\) is not the formula involving \(A_0\).
\(5.65\sqrt {{A_0}}\): This formula directly relates the gauge length \(L_0\) to the initial cross-sectional area \(A_0\), consistent with standard codal provisions for many types of specimens.
6d: While some specific tests or specimen types might use a ratio of 6d, 5d is more commonly cited as the basis for standard specimens related to the \(5.65\sqrt{A_0}\) formula.
8d: This ratio is generally not the standard basis for calculating gauge length in relation to the \(5.65\sqrt{A_0}\) formula.
Based on standard practices and the relationship derived from common cylindrical specimen dimensions, the gauge length of a steel specimen as per codal provision is typically given by the formula involving the initial cross-sectional area \((A_0)\).
Therefore, the correct option is the one that uses the \(5.65\sqrt {{A_0}}\) formula.
| Specimen Type / Basis | Common Gauge Length Formula \((L_0)\) | Notes |
|---|---|---|
| Standard Cylindrical Specimen | \(5d\) | Where \(d\) is the original diameter. Basis for the area-based formula. |
| Specimens based on Cross-sectional Area | \(5.65\sqrt{A_0}\) | Where \(A_0\) is the original cross-sectional area. Applicable to various shapes (circular, square) related to the 5d standard. |
| Other Proportional Specimens | \(Kd\) or \(K\sqrt{A_0}\) | \(K\) is a proportionality constant; 5 and 5.65 are standard values for many codes. |
Using a standard gauge length is crucial in tensile testing for several reasons:
The formula \(L_0 = 5.65\sqrt{A_0}\) is widely recognized and applied when calculating the required gauge length based on the specimen's cross-sectional area, making it a fundamental aspect of tensile testing procedures as per codal provisions.
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