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Question

Furan has ____________ Π e- plus an unshared pair of oxygen sp2 orbital.

The correct answer is

6

Understanding Furan Structure and Pi Electrons

Furan is a fascinating example of a heterocyclic aromatic compound. It's a five-membered ring containing four carbon atoms and one oxygen atom. The ring structure includes two double bonds.

To determine the number of $\Pi$ electrons in Furan, we need to count the electrons that are part of the molecule's $\Pi$ system.

Counting Furan's Pi Electrons

The $\Pi$ electron system in Furan is formed by the following:

  • Each double bond in the ring contributes 2 $\Pi$ electrons. Furan has two double bonds, so this accounts for $2 \times 2 = 4$ $\Pi$ electrons.
  • The oxygen atom in the ring contributes one of its lone pairs to the $\Pi$ system. Oxygen has two lone pairs. Due to the geometry and bonding in Furan, one lone pair resides in an sp2 orbital and is localized in the plane of the ring. This pair does NOT participate in the $\Pi$ system. The other lone pair resides in a p-orbital that is perpendicular to the ring plane and can overlap with the p-orbitals of the carbon atoms, thus participating in the $\Pi$ system. This lone pair contributes 2 $\Pi$ electrons.

The question correctly highlights the unshared pair of oxygen in an sp2 orbital, indicating that this specific pair is not the one contributing to the $\Pi$ system.

Therefore, the total number of $\Pi$ electrons in Furan is the sum of electrons from the double bonds and the contributing lone pair from oxygen:

Total $\Pi$ electrons = (Electrons from 2 double bonds) + (Electrons from oxygen's lone pair in p-orbital)

Total $\Pi$ electrons = $4 + 2 = 6$

Furan's Aromaticity and Hückel's Rule

The presence of 6 $\Pi$ electrons in a cyclic, planar molecule like Furan is consistent with Hückel's rule for aromaticity, which states that an aromatic system must have $(4n + 2)$ $\Pi$ electrons, where $n$ is a non-negative integer ($n=0, 1, 2, ...$). For Furan, with 6 $\Pi$ electrons, if we set $4n + 2 = 6$, we get $4n = 4$, which means $n = 1$. Since $n=1$ is an integer, Furan satisfies Hückel's rule and is aromatic.

Conclusion

Based on the structure and electron distribution in Furan, it contains 4 $\Pi$ electrons from the two double bonds and 2 $\Pi$ electrons from one of the oxygen's lone pairs (the one in the p-orbital). The other lone pair on oxygen is in an sp2 orbital and is not part of the $\Pi$ system. Thus, Furan has a total of 6 $\Pi$ electrons.

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Important Questions from Heterocyclic Compounds

  1. For the two statements given below, analyse for the following:

    (a) Pyridine and Pyrrole both are weak bases, but pyridine is much more basic than pyrrole.

    (b) Lone pair associated with nitrogen in Pyridine is entirely with nitrogen and not delocalised into the aromatic Π system, whereas in Pyrrole unshared pair belonging to nitrogen must be added to the 4Π e- of 2 double bonds and thus is delocalised into the aromatic Π system.

  2. Which one of the following compound is analogue of benzene ?
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