Problem Solution
Given:
- Speed of each cab = 74 km/h
- Time gap between two cabs = 28 minutes
- Man meets cabs at interval = 10 minutes
- Direction: Opposite
Step 1: Convert time into hours
28 minutes = 28/60 = 7/15 hours
10 minutes = 10/60 = 1/6 hours
Step 2: Head start distance of first cab
Distance = Speed × Time
= 74 × (7/15)
= 518/15 km
Step 3: Relative speed
Since opposite directions:
Relative speed = 74 + x
Step 4: Apply condition
Distance / Relative speed = Time difference
(518/15) ÷ (74 + x) = 1/6
Step 5: Solve equation
(518/15) × 6 = 74 + x
3108/15 = 74 + x
207.2 = 74 + x
x = 133.2
Final Answer Speed of the man = 133.2 km/h
Important Questions from Speed Time and Distance
A train travelling at a speed of 72 km/hr crosses a post in 20 seconds. If it crosses another train travelling at a speed of 54 km/hr in the same direction in 1 minute 45 seconds, then the difference in length between the two trains is
Rajiv's boat can travel along the current at the 8 km/hour and against the current at the rate 6 km/hour. Find the time taken by the boat to sail 28 km in still water.
Rohit and Dinesh are 64 km apart. Rohit can walk at a speed of 15 km/hr and Dinesh at the speed of 17 km/hr. In how many hours will they meet if they are travelling towards each other?
Two trains running in opposite directions cross a man standing on the platform in 25 seconds and 32 seconds respectively and they cross each other in 30 seconds. The ratio of their speed is:
A worker covers a distance of 81 km in 11 hours. He travels partly on foot at 4.5 km/h and partly on bicycle at 15 km/h. What is the distance covered on the cycle?
