Problem Solution
Given:
- Speed of each cab = 74 km/h
- Time gap between two cabs = 28 minutes
- Man meets cabs at interval = 10 minutes
- Direction: Opposite
Step 1: Convert time into hours
28 minutes = 28/60 = 7/15 hours
10 minutes = 10/60 = 1/6 hours
Step 2: Head start distance of first cab
Distance = Speed × Time
= 74 × (7/15)
= 518/15 km
Step 3: Relative speed
Since opposite directions:
Relative speed = 74 + x
Step 4: Apply condition
Distance / Relative speed = Time difference
(518/15) ÷ (74 + x) = 1/6
Step 5: Solve equation
(518/15) × 6 = 74 + x
3108/15 = 74 + x
207.2 = 74 + x
x = 133.2
Final Answer Speed of the man = 133.2 km/h
Important Questions from Speed Time and Distance
The average speed of a train is 180% of the average speed of a car. The car covers a distance of 990 km in 15 hours. The time taken (in hours) by the train to cover the distance of 891 km is:
If Rohit can cover a distance of 1188 km in 22 hours, then what is the speed of Rohit?
A train is moving at 72 km/hrs. The distance covers in 15 minutes by the train is:
If Sonu is driving a car at a speed of 20 m/s, then in how much time Sonu will cover a distance of 936 km?
A person crosses a 1600 m long street in 4 min. What is his speed (in km/h)?
