Problem Solution
Given:
- Speed of each cab = 74 km/h
- Time gap between two cabs = 28 minutes
- Man meets cabs at interval = 10 minutes
- Direction: Opposite
Step 1: Convert time into hours
28 minutes = 28/60 = 7/15 hours
10 minutes = 10/60 = 1/6 hours
Step 2: Head start distance of first cab
Distance = Speed × Time
= 74 × (7/15)
= 518/15 km
Step 3: Relative speed
Since opposite directions:
Relative speed = 74 + x
Step 4: Apply condition
Distance / Relative speed = Time difference
(518/15) ÷ (74 + x) = 1/6
Step 5: Solve equation
(518/15) × 6 = 74 + x
3108/15 = 74 + x
207.2 = 74 + x
x = 133.2
Final Answer Speed of the man = 133.2 km/h
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