2secθ
The problem asks us to simplify a given trigonometric expression and find which of the options it is equal to. The expression involves several trigonometric ratios like tan, sec, cot, and cosec. To simplify complex trigonometric expressions, it is often helpful to convert all terms into their basic sine and cosine forms.
The given expression is:
\(\frac{(1 + tan\theta + sec\theta)(1 + cot\theta - cosec\theta)}{(sec\theta + tan\theta)(1 - sin\theta)}\)
Let's convert each trigonometric ratio into its equivalent sine and cosine form:
The numerator is \((1 + tan\theta + sec\theta)(1 + cot\theta - cosec\theta)\). Substitute the sine and cosine forms:
\((1 + \frac{sin\theta}{cos\theta} + \frac{1}{cos\theta})(1 + \frac{cos\theta}{sin\theta} - \frac{1}{sin\theta})\)
Combine terms within each parenthesis by finding a common denominator:
\((\frac{cos\theta + sin\theta + 1}{cos\theta})(\frac{sin\theta + cos\theta - 1}{sin\theta})\)
Now, multiply the two fractions. The numerator becomes \((cos\theta + sin\theta + 1)(sin\theta + cos\theta - 1)\). This looks like \((a+b)(a-b)\) where \(a = cos\theta + sin\theta\) and \(b = 1\). Using the difference of squares formula, \(a^2 - b^2\):
\((cos\theta + sin\theta)^2 - 1^2\)
Expand \((cos\theta + sin\theta)^2\):
\(cos^2\theta + sin^2\theta + 2sin\theta cos\theta\)
Using the identity \(cos^2\theta + sin^2\theta = 1\):
\(1 + 2sin\theta cos\theta\)
So, the numerator of the combined fraction is \((1 + 2sin\theta cos\theta) - 1 = 2sin\theta cos\theta\). The denominator of the combined fraction is \(cos\theta sin\theta\). Thus, the simplified numerator of the original expression is:
\(\frac{2sin\theta cos\theta}{cos\theta sin\theta} = 2\)
The denominator of the original expression is \((sec\theta + tan\theta)(1 - sin\theta)\). Substitute the sine and cosine forms for the first part:
\((\frac{1}{cos\theta} + \frac{sin\theta}{cos\theta})(1 - sin\theta)\)
Combine terms within the parenthesis:
\((\frac{1 + sin\theta}{cos\theta})(1 - sin\theta)\)
Multiply the fractions:
\(\frac{(1 + sin\theta)(1 - sin\theta)}{cos\theta}\)
The numerator is \((1 + sin\theta)(1 - sin\theta)\), which is in the form \((a+b)(a-b)\). Using the difference of squares formula, \(a^2 - b^2\):
\(1^2 - sin^2\theta = 1 - sin^2\theta\)
Using the identity \(1 - sin^2\theta = cos^2\theta\):
\(cos^2\theta\)
So, the simplified denominator is:
\(\frac{cos^2\theta}{cos\theta} = cos\theta\)
Now substitute the simplified numerator (which is 2) and the simplified denominator (which is \(cos\theta\)) back into the original expression:
\(\frac{2}{cos\theta}\)
Since \(sec\theta = \frac{1}{cos\theta}\), we can write this as:
\(2 \times \frac{1}{cos\theta} = 2sec\theta\)
The simplified expression is \(2sec\theta\).
| Identity | Formula |
|---|---|
| Pythagorean Identity | \(sin^2\theta + cos^2\theta = 1\) |
| Reciprocal Identity (sec) | \(sec\theta = \frac{1}{cos\theta}\) |
| Reciprocal Identity (cosec) | \(cosec\theta = \frac{1}{sin\theta}\) |
| Reciprocal Identity (cot) | \(cot\theta = \frac{1}{tan\theta}\) |
| Quotient Identity (tan) | \(tan\theta = \frac{sin\theta}{cos\theta}\) |
| Quotient Identity (cot) | \(cot\theta = \frac{cos\theta}{sin\theta}\) |
| Difference of Squares | \((a+b)(a-b) = a^2 - b^2\) |
Simplifying trigonometric expressions often involves using fundamental identities to rewrite the expression in a simpler form. A common strategy, as used in this problem, is to convert all terms into sine and cosine. Other useful techniques include:
Practice is key to becoming proficient in recognizing which identities and techniques to apply to simplify a given trigonometric expression.
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