Four persons P, Q, R and S are to be seated in a row. R should not be seated at the second position from the left end of the row. The number of distinct seating arrangements possible is:
We need to find the number of distinct ways to seat 4 persons (P, Q, R, S) in a row, with the constraint that R cannot be in the second position from the left.
Without any restrictions, the 4 persons can be arranged in the 4 seats in $4!$ ways.
Calculation: $4! = 4 \times 3 \times 2 \times 1 = 24$. So, there are 24 total possible seating arrangements.
Now, let's calculate the number of arrangements where R is seated in the second position (the restricted position).
If R is fixed in the second position, the remaining 3 persons (P, Q, S) can be arranged in the remaining 3 positions (1st, 3rd, 4th) in $3!$ ways.
Calculation: $3! = 3 \times 2 \times 1 = 6$. There are 6 arrangements where R is in the second position.
To find the number of arrangements where R is *not* in the second position, we subtract the number of violating arrangements from the total number of arrangements.
Possible Arrangements = Total Arrangements - Arrangements where R is in the second position
Calculation: $24 - 6 = 18$.
Therefore, there are 18 distinct seating arrangements possible where R is not seated at the second position from the left.
Three distinct sets of indistinguishable twins are to be seated at a circular table that has 8 identical chairs. Unique seating arrangements are defined by the relative positions of the people.
How many unique seating arrangements are possible such that each person is sitting next to their twin?
Two wizards try to create a spell using all the four elements, water, air, fire, and earth. For this, they decide to mix all these elements in all possible orders. They also decide to work independently. After trying all possible combination of elements, they conclude that the spell does not work.
How many attempts does each wizard make before coming to this conclusion, independently?