Four persons P, Q, R and S are to be seated in a row. R should not be seated at the second position from the left end of the row. The number of distinct seating arrangements possible is:
We need to find the number of distinct ways to seat 4 persons (P, Q, R, S) in a row, with the constraint that R cannot be in the second position from the left.
Without any restrictions, the 4 persons can be arranged in the 4 seats in $4!$ ways.
Calculation: $4! = 4 \times 3 \times 2 \times 1 = 24$. So, there are 24 total possible seating arrangements.
Now, let's calculate the number of arrangements where R is seated in the second position (the restricted position).
If R is fixed in the second position, the remaining 3 persons (P, Q, S) can be arranged in the remaining 3 positions (1st, 3rd, 4th) in $3!$ ways.
Calculation: $3! = 3 \times 2 \times 1 = 6$. There are 6 arrangements where R is in the second position.
To find the number of arrangements where R is *not* in the second position, we subtract the number of violating arrangements from the total number of arrangements.
Possible Arrangements = Total Arrangements - Arrangements where R is in the second position
Calculation: $24 - 6 = 18$.
Therefore, there are 18 distinct seating arrangements possible where R is not seated at the second position from the left.
A police station has six personnel comprising an inspector (I) and five constables ($C_1, C_2, C_3, C_4, C_5$). Normally, a 'raid team' of two, three, or four members is formed depending upon the nature of the raid. As per rule, it is mandatory that the inspector is part of raid team.
Number of distinct raid teams that can be formed is __________________.
(Answer in integer)
Five teams have to compete in a league, with every team playing every other team exactly once, before going to the next round. How many matches will have to be held to complete the league round of matches?