Four persons P, Q, R and S are to be seated in a row. R should not be seated at the second position from the left end of the row. The number of distinct seating arrangements possible is:
18
The problem asks us to find the number of distinct seating arrangements for four persons P, Q, R, and S in a row, with a specific condition: R should not be seated at the second position from the left end of the row.
First, let us determine the total number of ways to arrange four distinct persons (P, Q, R, S) in four positions in a row without any restrictions. This is a classic permutation problem. For 'n' distinct items to be arranged in 'n' positions, the number of permutations is given by $n!$ (n factorial).
Let's calculate the factorial:
$\qquad 4! = 4 \times 3 \times 2 \times 1 = 24$
So, there are 24 distinct ways to seat P, Q, R, and S in a row without any specific conditions.
The problem states a constraint: R should not be seated at the second position from the left end of the row. To solve this, it's often easier to find the number of arrangements where the condition is violated (i.e., R is seated at the second position), and then subtract this from the total number of arrangements.
Let's consider the scenario where R is fixed at the second position from the left. The positions are represented as follows:
_ _ _ _
If R is at the second position, it looks like this:
_ R _ _
Now, we have 3 remaining persons (P, Q, S) and 3 remaining positions (1st, 3rd, and 4th). The number of ways to arrange these 3 persons in the 3 remaining positions is $3!$ (3 factorial).
Let's calculate this factorial:
$\qquad 3! = 3 \times 2 \times 1 = 6$
So, there are 6 arrangements where person R is seated at the second position from the left.
To find the number of distinct seating arrangements where R is not seated at the second position, we subtract the "unwanted" arrangements (where R is at the second position) from the total possible arrangements.
Number of distinct seating arrangements satisfying the condition = (Total arrangements) - (Arrangements where R is at the second position)
$\qquad \text{Distinct arrangements} = 24 - 6 = 18$
Therefore, there are 18 distinct seating arrangements possible where R is not seated at the second position from the left end of the row.
In summary, by using the principles of permutations and addressing the specific constraint, we found that the total number of distinct ways to seat the four persons P, Q, R, and S, such that R is not at the second position, is 18.
| Step | Description | Calculation |
|---|---|---|
| 1 | Total arrangements of 4 persons | $4! = 24$ |
| 2 | Arrangements with R fixed at 2nd position | $3! = 6$ |
| 3 | Distinct arrangements (Step 1 - Step 2) | $24 - 6 = 18$ |
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