The unit digit of a product depends solely on the unit digits of the numbers being multiplied. The possible unit digits for any natural number are 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9.
We require the unit digit of the product of four natural numbers to be 1, 3, 7, or 9. This outcome is achievable only if the unit digit of each of the four selected numbers is also from the set {1, 3, 7, 9}.
Consider a single randomly selected natural number:
$ P(\text{Unit digit} \in \{1, 3, 7, 9\}) = \frac{\text{Number of favorable digits}}{\text{Total possible digits}} = \frac{4}{10} = \frac{2}{5} $
Since the four natural numbers are selected randomly and independently, the probability that all four numbers have unit digits from {1, 3, 7, 9} is the product of their individual probabilities:
$ P(\text{Product unit digit} \in \{1, 3, 7, 9\}) = P(\text{1st has favorable unit digit}) \times P(\text{2nd has favorable unit digit}) \times P(\text{3rd has favorable unit digit}) \times P(\text{4th has favorable unit digit}) $
$ P(\text{Product unit digit} \in \{1, 3, 7, 9\}) = \left( \frac{2}{5} \right) \times \left( \frac{2}{5} \right) \times \left( \frac{2}{5} \right) \times \left( \frac{2}{5} \right) = \left( \frac{2}{5} \right)^4 $
Calculating the final value:
$ \left( \frac{2}{5} \right)^4 = \frac{2^4}{5^4} = \frac{16}{625} $
The probability that the unit's digit of the product of four randomly selected natural numbers is 1, 3, 7, or 9 is $\frac{16}{625}$.