In steady adiabatic throttling with no shaft work and negligible kinetic and potential energy changes, which specific thermodynamic property remains constant?
Enthalpy
For steady adiabatic throttling with zero shaft work and negligible kinetic and potential energy changes, the flow-energy equation reduces to \(h_1=h_2\). Thus specific enthalpy remains constant.
Important Questions from First Law of Thermodynamics
Heat transfer in a cyclic process are +20 kJ, -5 kJ, -10 kJ and +15kJ. Net work done for this cycle will be given by:
An open system is one in which ______.
A system will be in thermodynamic equilibrium only if it is in ____.
A. Thermal equilibrium
B. Mechanical equilibrium
C. Chemical equilibrium
The gas constant (R) is equal to the _____ of two specific heats.
In a reversible adiabatic process the ration \(\left( {\frac{{{T_1}}}{{{T_2}}}} \right)\) is equal to:
