For semiconductor, with both electrons and holes as carriers, the resistivity can be expressed as:
Resistivity ($\rho$) is a fundamental property of a material that measures how strongly it resists the flow of electric current. Its unit is ohm-meter ($\Omega \cdot \text{m}$). In semiconductors, electrical conduction occurs due to the movement of charge carriers, which can be both electrons and holes.
The reciprocal of resistivity is conductivity ($\sigma$), which measures how easily current flows through a material. The relationship is given by:
\(\rho = \frac{1}{\sigma}\)
The unit of conductivity is siemens per meter ($\text{S}/\text{m}$), or $\Omega^{-1} \cdot \text{m}^{-1}$.
In a semiconductor where both electrons and holes are present as charge carriers, the total electrical conductivity is the sum of the conductivity due to electrons and the conductivity due to holes. This is because both types of carriers contribute to the overall current flow.
Electrons are negatively charged carriers. Their contribution to conductivity depends on their concentration and how easily they move through the material (their mobility). The formula for electron conductivity is:
\(\sigma_n = n q \mu_n\)
Where:
Holes are positively charged carriers. Similar to electrons, their contribution to conductivity depends on their concentration and mobility. The formula for hole conductivity is:
\(\sigma_p = p q \mu_p\)
Where:
The total conductivity of the semiconductor is the sum of the conductivity due to electrons and the conductivity due to holes:
\(\sigma = \sigma_n + \sigma_p\)
Substituting the formulas for \(\sigma_n\) and \(\sigma_p\):
\(\sigma = n q \mu_n + p q \mu_p\)
We can factor out the elementary charge \(q\):
\(\sigma = q (n \mu_n + p \mu_p)\)
Or, written slightly differently as often seen:
\(\sigma = q (\mu_n n + \mu_p p)\)
Since resistivity ($\rho$) is the reciprocal of conductivity ($\sigma$), we can find the expression for resistivity by taking the reciprocal of the total conductivity formula:
\(\rho = \frac{1}{\sigma} = \frac{1}{q (\mu_n n + \mu_p p)}\)
Let's compare our derived formula for semiconductor resistivity with the given options:
Therefore, the correct expression for the resistivity of a semiconductor with both electrons and holes as carriers is \(\rm \frac{1}{q(\mu_n n + \mu _p p)}\).
| Symbol | Meaning | Unit (SI) |
|---|---|---|
| \(\rho\) | Resistivity | \(\Omega \cdot \text{m}\) |
| \(\sigma\) | Conductivity | \(\text{S}/\text{m}\) |
| \(n\) | Electron concentration | \(\text{m}^{-3}\) |
| \(p\) | Hole concentration | \(\text{m}^{-3}\) |
| \(q\) | Elementary charge magnitude | C |
| \(\mu_n\) | Electron mobility | \(\text{m}^2/\text{V} \cdot \text{s}\) |
| \(\mu_p\) | Hole mobility | \(\text{m}^2/\text{V} \cdot \text{s}\) |
| Property | Description | Dependence |
|---|---|---|
| Resistivity (\(\rho\)) | Resistance to current flow | Inverse of conductivity, depends on carrier concentration and mobility |
| Conductivity (\(\sigma\)) | Ease of current flow | Sum of electron and hole conductivity, depends on \(n, p, \mu_n, \mu_p\) |
| Carrier Concentration (\(n, p\)) | Number of charge carriers per unit volume | Temperature, doping level |
| Mobility (\(\mu_n, \mu_p\)) | Ease of movement in electric field | Temperature, scattering mechanisms (impurities, lattice vibrations) |
In semiconductors, charge carriers move under the influence of an electric field (drift) and due to concentration gradients (diffusion). Resistivity and conductivity are primarily related to drift current, which is proportional to the electric field and the total charge density and drift velocity of carriers.
The drift velocity (\(v_d\)) of a carrier is proportional to the electric field (\(E\)), with the proportionality constant being the mobility ($\mu$):
\(v_d = \mu E\)
The current density (\(J\)) due to drift is given by the charge density multiplied by the drift velocity. For electrons:
\(J_n = (-nq) v_{dn} = (-nq) (-\mu_n E) = n q \mu_n E\)
For holes:
\(J_p = (pq) v_{dp} = (pq) (\mu_p E) = p q \mu_p E\)
The total current density is the sum:
\(J = J_n + J_p = (n q \mu_n + p q \mu_p) E\)
We know that current density is also related to conductivity and electric field by Ohm's Law in differential form:
\(J = \sigma E\)
Comparing the two expressions for \(J\), we get:
\(\sigma E = (n q \mu_n + p q \mu_p) E\)
So, the total conductivity is:
\(\sigma = n q \mu_n + p q \mu_p = q (n \mu_n + p \mu_p)\)
And finally, resistivity is the reciprocal of this conductivity:
\(\rho = \frac{1}{\sigma} = \frac{1}{q (n \mu_n + p \mu_p)}\)
This detailed derivation confirms the formula for semiconductor resistivity when both electrons and holes are present.
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