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Question

For maximum efficiency, the intermediate pressure, P2, in 2-stage reciprocating compressor should be

The correct answer is \(\sqrt{P_1\times P_3}\)

Compressor Efficiency: Multi-Stage Compression Basics

Multi-stage compression is a technique used in reciprocating compressors to increase efficiency and reduce the overall work required to compress a gas from an initial pressure (\(P_1\)) to a final high pressure (\(P_3\)). Instead of compressing the gas in a single stage, it is compressed in two or more stages with intercooling between stages. Intercooling cools the gas back to its initial temperature, which helps reduce the work input.

For a 2-stage reciprocating compressor, the gas is first compressed from \(P_1\) to an intermediate pressure \(P_2\) in the first stage. Then, it is cooled (intercooled) to the initial temperature \(T_1\) before being compressed from \(P_2\) to the final pressure \(P_3\) in the second stage. The goal is to determine the optimal intermediate pressure (\(P_2\)) that leads to maximum efficiency, which translates to minimum total work input.

Maximum Efficiency: Work Done in Two Stages

For maximum efficiency in a 2-stage reciprocating compressor with perfect intercooling (i.e., cooling the gas back to the initial temperature \(T_1\) after the first stage), the work done in each stage should be equal. This condition ensures that the total work required for compression is minimized.

The work done during a polytropic compression process for a single stage is given by the formula:

\(W = \frac{n}{n-1} m R T_1 \left[ \left(\frac{P_{discharge}}{P_{suction}}\right)^{\frac{n-1}{n}} - 1 \right]\)

Where:

  • \(n\) is the polytropic index
  • \(m\) is the mass of the gas
  • \(R\) is the specific gas constant
  • \(T_1\) is the initial temperature
  • \(P_{discharge}\) is the discharge pressure
  • \(P_{suction}\) is the suction pressure

For the first stage (from \(P_1\) to \(P_2\)):

\(W_1 = \frac{n}{n-1} m R T_1 \left[ \left(\frac{P_2}{P_1}\right)^{\frac{n-1}{n}} - 1 \right]\)

For the second stage (from \(P_2\) to \(P_3\), assuming perfect intercooling to \(T_1\)):

\(W_2 = \frac{n}{n-1} m R T_1 \left[ \left(\frac{P_3}{P_2}\right)^{\frac{n-1}{n}} - 1 \right]\)

Intermediate Pressure: Deriving the Optimal Value

To achieve maximum efficiency (minimum total work), the work done in the first stage must be equal to the work done in the second stage:

\(W_1 = W_2\)

Substituting the work formulas:

\(\frac{n}{n-1} m R T_1 \left[ \left(\frac{P_2}{P_1}\right)^{\frac{n-1}{n}} - 1 \right] = \frac{n}{n-1} m R T_1 \left[ \left(\frac{P_3}{P_2}\right)^{\frac{n-1}{n}} - 1 \right]\)

Since the terms \(\frac{n}{n-1} m R T_1\) are common on both sides and non-zero, we can cancel them out:

\(\left[ \left(\frac{P_2}{P_1}\right)^{\frac{n-1}{n}} - 1 \right] = \left[ \left(\frac{P_3}{P_2}\right)^{\frac{n-1}{n}} - 1 \right]\)

Adding 1 to both sides:

\(\left(\frac{P_2}{P_1}\right)^{\frac{n-1}{n}} = \left(\frac{P_3}{P_2}\right)^{\frac{n-1}{n}}\)

Since the exponents are equal, the bases must be equal:

\(\frac{P_2}{P_1} = \frac{P_3}{P_2}\)

Cross-multiplying to solve for \(P_2\):

\(P_2 \times P_2 = P_1 \times P_3\)

\(P_2^2 = P_1 \times P_3\)

Taking the square root of both sides:

\(P_2 = \sqrt{P_1 \times P_3}\)

Optimal Intermediate Pressure for Reciprocating Compressors

Therefore, for maximum efficiency in a 2-stage reciprocating compressor with perfect intercooling, the intermediate pressure (\(P_2\)) should be the geometric mean of the initial pressure (\(P_1\)) and the final pressure (\(P_3\)).

This condition ensures that the pressure ratio across each stage is the same, leading to minimum overall work input and thus maximum efficiency.

Based on the derivation, the correct intermediate pressure \(P_2\) for maximum efficiency is \(\sqrt{P_1\times P_3}\).

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Important Questions from Reciprocating Compressors

  1. The principle of single stroke reciprocating compressor is similar to:

  2. The volumetric efficiency of a reciprocating compressor

  3. In a reciprocating compressor, one should aim at compressing the air

  4. The suction pressure is 1 bar and the delivery pressure is 125 bar. What is the ideal intermediate pressure at the end of first stage for a 3-stage air compressor?

  5. In a double-acting compressor, the air is compressed

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