For how many integral values of k, the equation x2 - 4x + k = 0, where k is an integer has real roots and both of them lie in the interval (0, 5) ?
4
The problem asks for the number of integer values of $\small k$ for which the quadratic equation $\small x^2 - 4x + k = 0$ has real roots, and both of these roots lie strictly between 0 and 5 (i.e., in the interval $\small (0, 5)$).
For a quadratic equation of the form $\small ax^2 + bx + c = 0$, several conditions must be met for the roots to be real and lie within a specific interval $\small (p, q)$. In our equation, $\small a = 1$, $\small b = -4$, and $\small c = k$. The interval is $\small (p, q) = (0, 5)$. Since $\small a=1$ is positive, the parabola opens upwards.
A quadratic equation has real roots if and only if its discriminant, $\small \Delta = b^2 - 4ac$, is greater than or equal to zero.
For $\small x^2 - 4x + k = 0$, the discriminant is:
$\small \Delta = (-4)^2 - 4(1)(k) = 16 - 4k$
For real roots, we must have:
$\small 16 - 4k \ge 0$
$\small 16 \ge 4k$
$\small 4 \ge k$
So, $\small k \le 4$. This is our first condition on $\small k$.
For a quadratic equation $\small f(x) = ax^2 + bx + c = 0$ with $\small a > 0$, for both roots to lie in the interval $\small (p, q)$, the following conditions must be satisfied:
Let's apply these conditions to $\small f(x) = x^2 - 4x + k$ and the interval $\small (0, 5)$:
We already found this condition:
$\small k \le 4$
Substitute $\small x = 0$ into the equation $\small f(x) = x^2 - 4x + k$:
$\small f(0) = (0)^2 - 4(0) + k = k$
For the roots to be in $\small (0, 5)$, we need $\small f(0) > 0$ (as the parabola opens upwards, if $\small f(0) \le 0$, at least one root would be less than or equal to 0).
$\small k > 0$
Substitute $\small x = 5$ into the equation $\small f(x) = x^2 - 4x + k$:
$\small f(5) = (5)^2 - 4(5) + k = 25 - 20 + k = 5 + k$
For the roots to be in $\small (0, 5)$, we need $\small f(5) > 0$ (similarly, if $\small f(5) \le 0$, at least one root would be greater than or equal to 5).
$\small 5 + k > 0$
$\small k > -5$
The x-coordinate of the vertex is given by $\small -b/(2a)$. For $\small x^2 - 4x + k = 0$, the vertex x-coordinate is:
$\small -(-4)/(2 \times 1) = 4/2 = 2$
The condition is that the vertex must lie in $\small (0, 5)$. So, $\small 0 < 2 < 5$. This statement is true. This condition does not impose any further restrictions on the value of $\small k$.
We have the following conditions for $\small k$:
We need to find the values of $\small k$ that satisfy all three inequalities simultaneously. Combining $\small k > 0$ and $\small k > -5$, we get $\small k > 0$. Combining $\small k > 0$ and $\small k \le 4$, we get the range for $\small k$ as:
$\small 0 < k \le 4$
The problem asks for the number of integral values of $\small k$. The integers $\small k$ that satisfy $\small 0 < k \le 4$ are the integers greater than 0 and less than or equal to 4.
These integers are 1, 2, 3, and 4.
Let's check each value:
The integral values of $\small k$ that satisfy all conditions are 1, 2, 3, and 4.
There are 4 such integral values.
The integral values of $\small k$ for which the equation $\small x^2 - 4x + k = 0$ has real roots and both roots lie in the interval $\small (0, 5)$ are 1, 2, 3, and 4.
The number of such integral values is 4.
| Condition | Requirement | Calculation for $\small x^2 - 4x + k = 0$ | Resulting Inequality for $\small k$ |
|---|---|---|---|
| Real Roots | $\small \Delta \ge 0$ | $\small (-4)^2 - 4(1)(k) \ge 0$ $\small \Rightarrow$ $\small 16 - 4k \ge 0$ | $\small k \le 4$ |
| Root location (for $\small a>0$) | $\small f(0) > 0$ | $\small (0)^2 - 4(0) + k > 0$ | $\small k > 0$ |
| Root location (for $\small a>0$) | $\small f(5) > 0$ | $\small (5)^2 - 4(5) + k > 0$ $\small \Rightarrow$ $\small 25 - 20 + k > 0$ | $\small k > -5$ |
| Vertex location | $\small 0 < -b/(2a) < 5$ | $\small -(-4)/(2 \times 1) = 2$. Check $\small 0 < 2 < 5$. | Always true |
Understanding the location of roots for a quadratic equation $\small ax^2 + bx + c = 0$ is crucial for solving problems like this. The sign of $\small a$ determines the direction of the parabola. If $\small a > 0$, the parabola opens upwards; if $\small a < 0$, it opens downwards.
To determine if both roots lie within an interval $\small (p, q)$, besides ensuring real roots ($\small \Delta \ge 0$), we check the value of the function at the interval boundaries $\small p$ and $\small q$ and the position of the vertex.
These conditions help narrow down the possible values of the coefficients based on the desired location of the roots.
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