For an isotropic antenna P n(θ, φ) = 1, D = 1, for all θ and φ. The beam area for the isotropic antenna is given by:
4π
An isotropic antenna is a theoretical antenna that radiates power uniformly in all directions. This means its radiation pattern is spherical. It serves as a reference for comparing other antennas. Key properties of an isotropic antenna include:
The beam area (\(\Omega_A\)) of an antenna is a measure of the solid angle through which the antenna radiates power. It is defined as the integral of the normalized power pattern over the entire sphere (all solid angles).
Mathematically, the beam area is given by:
\[ \Omega_A = \int_{\text{sphere}} P_n(\theta, \phi) d\Omega \] where \(d\Omega = \sin(\theta) d\theta d\phi\) is the differential solid angle element.
Expanding the integral for the entire sphere (with \(\theta\) ranging from 0 to \(\pi\) and \(\phi\) ranging from 0 to \(2\pi\)):
\[ \Omega_A = \int_{0}^{2\pi} \int_{0}^{\pi} P_n(\theta, \phi) \sin(\theta) d\theta d\phi \]
For an isotropic antenna, we are given that \(P_n(\theta, \phi) = 1\) for all values of \(\theta\) and \(\phi\). Substituting this into the formula for beam area:
\[ \Omega_A = \int_{0}^{2\pi} \int_{0}^{\pi} (1) \sin(\theta) d\theta d\phi \]
We can separate this double integral into two single integrals:
\[ \Omega_A = \left( \int_{0}^{2\pi} d\phi \right) \left( \int_{0}^{\pi} \sin(\theta) d\theta \right) \]
First, evaluate the integral with respect to \(\phi\):
\[ \int_{0}^{2\pi} d\phi = [\phi]_{0}^{2\pi} = 2\pi - 0 = 2\pi \]
Next, evaluate the integral with respect to \(\theta\):
\[ \int_{0}^{\pi} \sin(\theta) d\theta = [-\cos(\theta)]_{0}^{\pi} = (-\cos(\pi)) - (-\cos(0)) = (-(-1)) - (-1) = 1 + 1 = 2 \]
Now, multiply the results of the two integrals to find the total beam area:
\[ \Omega_A = (2\pi) \times (2) = 4\pi \]
The beam area for an isotropic antenna is \(4\pi\) steradians. This is equal to the total solid angle of a sphere.
Alternatively, the directivity (D) and beam area (\(\Omega_A\)) are related by the formula:
\[ D = \frac{4\pi}{\Omega_A} \]
For an isotropic antenna, the directivity \(D = 1\). Substituting this value:
\[ 1 = \frac{4\pi}{\Omega_A} \]
Solving for \(\Omega_A\):
\[ \Omega_A = 4\pi \]
Both methods confirm that the beam area of an isotropic antenna is \(4\pi\) steradians.
Let's compare our calculated beam area with the given options:
Our calculated beam area of \(4\pi\) matches Option 2.
| Concept | Definition | Isotropic Antenna Value |
|---|---|---|
| Isotropic Antenna | Theoretical antenna radiating uniformly in all directions. | Reference standard. |
| Normalized Power Pattern (\(P_n\)) | Radiation intensity normalized to its maximum value. | 1 (constant). |
| Directivity (D) | Ratio of radiation intensity in a given direction to the average radiation intensity over all directions. | 1 (maximum value is same as average). |
| Beam Area (\(\Omega_A\)) | Solid angle containing all the radiated power, assuming constant intensity. | \(4\pi\) steradians. |
The beam area is an important parameter for understanding how concentrated an antenna's radiation is. A smaller beam area means the antenna concentrates power into a narrower region, resulting in higher directivity. The isotropic antenna, with a beam area equal to the total solid angle of a sphere (\(4\pi\)), represents the lowest possible directivity (D=1) and the largest possible beam area for a given amount of radiated power.
Real-world antennas always have directional patterns, meaning their \(P_n(\theta, \phi)\) varies with angle and is less than 1 in some directions and greater than 1 in others (except in the direction of maximum radiation, where \(P_n=1\) by definition). The beam area for a directional antenna will be smaller than \(4\pi\), and its directivity will be greater than 1.
The concept of solid angle is measured in steradians (sr). A full sphere subtends a solid angle of \(4\pi\) steradians.
Which of the following antennas is the standard reference antenna for the directiveness?
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(a) Fiber optic cable is much lighter than copper cable
(b) Fiber optic cable is not affected by power surges or electromagnetic interference
(c) Optical transmission is inherently bidirectional.
Which of the statements is (are) correct?Broadside arrays have
A. Number of dipoles of unequal size
B. Number of dipoles equally spaced
C. Collinear dipoles
D. Dipoles in phase
E. Dipoles are 90 out of phase
Choose the correct answer from the options given below:
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