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Question

For a Non-deterministic Finite Automaton (NDFA) with N number of states, the equivalent Deterministic Finite Automaton(DFA) has D number of states. Then, possible number of states in DFA can be defined as:

The correct answer is
$2^N$

Understanding NDFA to DFA State Conversion

This question concerns the relationship between the number of states in a Non-deterministic Finite Automaton (NDFA) and its equivalent Deterministic Finite Automaton (DFA). When converting an NDFA to an equivalent DFA, a common technique is the powerset construction.

Powerset Construction Explained

In an NDFA, a state transition can lead to multiple possible next states simultaneously, or even no specific next state for a given input symbol. A DFA, however, must transition to exactly one state for each input symbol.

The powerset construction works by defining each state in the equivalent DFA as a set of states from the original NDFA.

  • Let the original NDFA have $N$ states: {$q_0, q_1, ..., q_{N-1}$}.
  • The set of all possible states in the equivalent DFA corresponds to the powerset of the NDFA's states.
  • The powerset of a set with $N$ elements contains all possible subsets of those elements.
  • The number of subsets in the powerset of a set with $N$ elements is $2^N$.

Calculating Maximum DFA States

Therefore, each state in the equivalent DFA represents a unique subset of the NDFA's states. The maximum number of such subsets (and thus the maximum possible number of states in the equivalent DFA) is equal to the size of the powerset of the NDFA's state set.

If the NDFA has $N$ states, the maximum number of states in the equivalent DFA is $2^N$.

Analysis of Options

Let's analyze the given options:

  • Option 1: $N \times 2$ - This doesn't represent the combinatorial explosion of state combinations.
  • Option 2: $N + 2$ - This suggests a linear increase, which is incorrect for state combinations.
  • Option 3: $2^N$ - This correctly represents the size of the powerset, which is the maximum number of states needed for the equivalent DFA.
  • Option 4: $N \times D$ - This mixes the number of NDFA states ($N$) with the unknown number of DFA states ($D$), which isn't a direct formula for the maximum.

The possible number of states in the equivalent DFA can range from 1 (if the NDFA is simple) up to $2^N$ in the worst case.

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