This question concerns the view factor between the dome and the base of a hemispherical furnace.
The view factor, denoted as $F_{ij}$, represents the proportion of radiative energy leaving surface $i$ that directly strikes surface $j$. For any surface $i$ within a closed enclosure, the sum of the view factors to all surfaces $j$ it can see must equal 1. Mathematically, this is expressed as: $ \sum_{j} F_{ij} = 1 $
The diameter 'D' of the base is irrelevant for determining this specific view factor, as the geometry dictates that all radiation from the dome within the enclosure goes to the base.
The view factor from the dome to its base is 1.
| List-I | List-II |
| Electronic Configuration | First Ionisation energy (kJ mol$^{-1}$) |
| (A). ns$^2$ | (I). 2100 |
| (B). ns$^2$np$^1$ | (II). 1400 |
| (C). ns$^2$np$^3$ | (III). 800 |
| (D). ns$^2$np$^6$ | (IV). 900 |
| List-I | List-II |
| Spectroscopy | Property |
| (A). Raman | (I). Polarizability |
| (B). FTIR | (II). Dipole Moment |
| (C). UV-Visible | (III). Absorbance |
| (D). NMR | (IV). Spin |