For a common emitter connection of BJT, find the value of β if α = 0.995
199
This guide explains how to determine the current gain, beta ($\beta$), for a Bipolar Junction Transistor (BJT) in a common emitter configuration, using the provided alpha ($\alpha$) value.
In BJT theory, alpha ($\alpha$) represents the common-base current gain, which is the ratio of collector current change to emitter current change ($\alpha = \Delta I_C / \Delta I_E$). Beta ($\beta$) signifies the common-emitter current gain, the ratio of collector current change to base current change ($\beta = \Delta I_C / \Delta I_B$). Both are critical parameters for analyzing transistor behavior.
A direct relationship exists between $\alpha$ and $\beta$. The formula used to calculate $\beta$ when $\alpha$ is known is:
\beta = \frac{\alpha}{1 - \alpha}
Understanding this formula is key for converting between these two common measures of transistor gain.
The question provides the following value for alpha:
Follow these steps to calculate beta ($\beta$):
\beta = \frac{\alpha}{1 - \alpha}
\beta = \frac{0.995}{1 - 0.995}
1 - 0.995 = 0.005
\beta = \frac{0.995}{0.005}
\beta = 199
The calculation shows that the beta ($\beta$) value for the BJT is 199. This matches the first option provided in the question.
The __________ area in the transistor is considerably smaller than the collector area.
Secondary Breakdown occurs in -
For a bipolar junction transistor in common emitter mode, IC = maximum and VC (collector voltage) = VE (emitter voltage), the transistor operates in _____ mode.
High frequency transistors are designed especially for: