Surface energy ($\gamma$) relates to the energy required to create a new surface. It is influenced by atomic bonding and the arrangement of atoms on specific crystallographic planes.
For metals with a Body-Centered Cubic (bcc) structure, the atomic arrangement varies significantly between different planes:
Generally, less densely packed planes exhibit higher surface energies due to a greater number of unsatisfied bonds per surface atom. However, for many bcc metals, surface relaxation and specific bonding configurations modify this trend. Experimental and theoretical studies often show that the surface energy ranking is:
$ \gamma_{100} > \gamma_{110} $
This indicates that the surface energy per unit area of the (100) plane is typically greater than that of the (110) plane in bcc metals, contrary to what simple packing density might suggest.
The question asks for the ratio of the surface energy per unit area of the (100) plane to that of the (110) plane, which is $\frac{\gamma_{100}}{\gamma_{110}}$.
Given that $\gamma_{100} > \gamma_{110}$, the ratio $\frac{\gamma_{100}}{\gamma_{110}}$ will be greater than 1.
Based on established data for common bcc metals, this specific ratio is known to fall within a certain range.
The question states the correct value lies between 1.3 and 1.5. Therefore, the ratio $\frac{\gamma_{100}}{\gamma_{110}}$ for a bcc metal is approximately 1.3 to 1.5.
| Column I | Column II |
|---|---|
| (P) Tetragonal | (1) $a \neq b \neq c$, $\alpha = \beta = \gamma = 90^\circ$ |
| (Q) Rhombohedral | (2) $a = b \neq c$, $\alpha = \beta = \gamma = 90^\circ$ |
| (R) Orthorhombic | (3) $a \neq b \neq c$, $\alpha = \gamma = 90^\circ \neq \beta$ |
| (S) Monoclinic | (4) $a = b = c$, $\alpha = \beta = \gamma \neq 90^\circ$ |
The lattice parameter of face-centered cubic iron ($\gamma$-Fe) is 0.3571 nm. The radius (in nm) of the octahedral void in $\gamma$-Fe is _______________