$(\frac{13}{10})^4 \times (\frac{10}{13})^{16} \times (\frac{13}{10})^{17} = (\frac{10}{13})^{3m + 18}$
The problem requires finding the value of '$m$' by simplifying the given exponential equation:
$(\frac{13}{10})^4 \times (\frac{10}{13})^{16} \times (\frac{13}{10})^{17} = (\frac{10}{13})^{3m + 18}$
To simplify the LHS, we express all terms with a common base. We know that $(\frac{10}{13}) = (\frac{13}{10})^{-1}$. Substituting this into the equation:
$LHS = (\frac{13}{10})^4 \times ((\frac{13}{10})^{-1})^{16} \times (\frac{13}{10})^{17}$
Using the exponent rule $(a^x)^y = a^{x \times y}$:
$LHS = (\frac{13}{10})^4 \times (\frac{13}{10})^{-16} \times (\frac{13}{10})^{17}$
Using the exponent rule $a^x \times a^y = a^{x+y}$:
$LHS = (\frac{13}{10})^{4 + (-16) + 17}$
$LHS = (\frac{13}{10})^{5}$
Now, the equation becomes:
$(\frac{13}{10})^{5} = (\frac{10}{13})^{3m + 18}$
To solve for '$m$', we need the bases to be the same. We can rewrite the LHS base:
$LHS = ((\frac{10}{13})^{-1})^{5} = (\frac{10}{13})^{-5}$
The equation is now:
$(\frac{10}{13})^{-5} = (\frac{10}{13})^{3m + 18}$
Since the bases are equal, the exponents must be equal:
$-5 = 3m + 18$
Now, solve for '$m$':
$3m = -5 - 18$
$3m = -23$
$m = -\frac{23}{3}$
The value of '$m$' that satisfies the equation is $-\frac{23}{3}$.
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