Find the value of β for a BJT having α = 0.99.
This solution explains how to find the value of the common-emitter current gain, β, for a Bipolar Junction Transistor (BJT) given its common-base current gain, α.
Bipolar Junction Transistors (BJTs) have key parameters that describe their current amplifying capabilities:
Formula: $\alpha = \frac{\Delta I_C}{\Delta I_E}$
Formula: $\beta = \frac{\Delta I_C}{\Delta I_B}$
For any active BJT, there's a direct relationship between α and β. The formula connecting them is:
$$ \beta = \frac{\alpha}{1 - \alpha} $$
Conversely, if you know β, you can find α using:
$$ \alpha = \frac{\beta}{1 + \beta} $$
We are given the value of α = 0.99.
To find β, we use the formula:
$$ \beta = \frac{\alpha}{1 - \alpha} $$
Let's substitute the given value of α:
$$ \beta = \frac{0.99}{1 - 0.99} $$
$$ 1 - 0.99 = 0.01 $$
$$ \beta = \frac{0.99}{0.01} $$
$$ \beta = 99 $$
The calculated value of β for the BJT is 99. This value corresponds to the first option provided.
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