Find the value of 2.\(\overline {36} \) + 3.\(\overline {21} \) - 1.\(\overline {05} \)
4.\(\overline {52} \)
This question requires us to perform addition and subtraction operations on numbers expressed as repeating decimals. The goal is to find the value of the expression $2.\overline{36} + 3.\overline{21} - 1.\overline{05}$.
A repeating decimal is a decimal number where a sequence of digits repeats infinitely. The bar over the digits signifies the repeating block.
To perform the calculation accurately, we first convert each repeating decimal into its equivalent fraction form. We use algebra for this conversion.
Now substitute these fractions back into the original expression:
Expression = $x + y - z = \frac{234}{99} + \frac{318}{99} - \frac{104}{99}$
Since all fractions have the same denominator ($99$), we can combine the numerators:
Expression = $\frac{234 + 318 - 104}{99}$
First, add the positive terms: $234 + 318 = 552$.
Next, subtract the negative term: $552 - 104 = 448$.
So, the expression equals $\frac{448}{99}$.
The final step is to convert the resulting fraction $\frac{448}{99}$ back into a repeating decimal.
To do this, divide the numerator ($448$) by the denominator ($99$):
$\frac{448}{99} = 448 \div 99$
Performing the division:
$448 \div 99 = 4$ with a remainder of $52$. ($4 \times 99 = 396$; $448 - 396 = 52$).
This can be written as a mixed number: $4 \frac{52}{99}$.
The fractional part $\frac{52}{99}$ converts to the repeating decimal $0.525252...$, which is represented as $0.\overline{52}$.
Therefore, the value of the expression is $4.\overline{52}$.
Simplify
6 × {28 ÷ 84 × {36 × 49 ÷ (6 × 7)}}.
Simplify.

Find the value of \(0.\overline {3{\rm{\;}}} {\rm{of\;}}0.\bar 5 \div 0.\bar 5{\rm{\;of}}\left( {0.\bar 7 - 0.\bar 4} \right)\)