Find the value of $(1+i)^4$.
$-4$
This section provides a detailed step-by-step explanation to find the value of the complex number expression $(1+i)^4$. We will simplify the expression using basic algebraic rules and the properties of the imaginary unit, $i$.
A complex number is typically written in the form $a + bi$, where '$a$' is the real part, '$b$' is the imaginary part, and '$i$' is the imaginary unit. The imaginary unit $i$ is defined such that $i^2 = -1$. To find the value of $(1+i)^4$, we need to multiply $(1+i)$ by itself four times.
A common strategy for calculating higher powers of complex numbers is to first compute the square of the base number and then square the result. This simplifies the process.
We can expand $(1+i)^2$ using the binomial expansion formula $(a+b)^2 = a^2 + 2ab + b^2$.
Here, $a = 1$ and $b = i$. Applying the formula:
$ (1+i)^2 = 1^2 + 2(1)(i) + i^2 $Recall that $i^2 = -1$. Substitute this value into the equation:
$ (1+i)^2 = 1 + 2i + (-1) $Now, simplify the expression by combining the real terms:
$ (1+i)^2 = 1 + 2i - 1 $ $ (1+i)^2 = 2i $So, we found that $(1+i)^2$ simplifies to $2i$.
We can rewrite $(1+i)^4$ as $((1+i)^2)^2$. This allows us to use the result we just calculated.
$ (1+i)^4 = \left( (1+i)^2 \right)^2 $Substitute the value $(1+i)^2 = 2i$ into the equation:
$ (1+i)^4 = (2i)^2 $Now, we need to square the complex number $2i$. This means squaring both the coefficient (2) and the imaginary unit ($i$):
$ (2i)^2 = 2^2 \times i^2 $Calculate the squares:
$ (2i)^2 = 4 \times i^2 $Again, substitute $i^2 = -1$:
$ (2i)^2 = 4 \times (-1) $Performing the final multiplication:
$ (2i)^2 = -4 $Therefore, the value of $(1+i)^4$ is $-4$.
The process to find the value of $(1+i)^4$ involved two main steps:
This step-by-step approach simplifies the calculation of powers for complex numbers.
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