Find the odd one out: 1, 8, 9, 36, 25, 216, 49
36
To find the odd one out in the sequence 1, 8, 9, 36, 25, 216, 49, we need to look for a pattern or a rule that applies to most of the numbers, but not to one particular number. Let's examine the properties of each number in the given sequence.
Let's try to express each number as a power (a base raised to an exponent).
| Number | Can be written as |
|---|---|
| 1 | \(1^2\) or \(1^3\) |
| 8 | \(2^3\) |
| 9 | \(3^2\) |
| 36 | \(6^2\) |
| 25 | \(5^2\) |
| 216 | \(6^3\) |
| 49 | \(7^2\) |
From the table above, we can see that most numbers are either a perfect square (raised to the power of 2) or a perfect cube (raised to the power of 3).
Let's look closely at the bases of these powers, especially distinguishing between squares and cubes.
Let's consider the bases used for the perfect squares in the sequence:
Notice a pattern here. All the perfect squares in the list (1, 9, 25, 49) are squares of odd numbers (1, 3, 5, 7). However, the number 36 is the square of the number 6, which is an even number.
Now let's look at the bases for the perfect cubes:
The pattern for the bases of the cubes doesn't show a consistent odd or even property like the squares do (they are 1, 2, 6).
Based on the observation regarding the bases of the perfect squares, the number 36 stands out. It is the only number in the sequence that is a perfect square of an even number, while all other perfect squares in the list are squares of odd numbers.
Therefore, 36 is the odd one out in the sequence.
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