Find the number whose 6 times is 6 less than 60. A. 6 B. 7 C. 8
D
The question asks us to find a specific number. We are given a condition about this number: its value when multiplied by 6 is equal to a value that is 6 less than 60.
Let's represent the unknown number with a variable. A common variable used in algebra is \(x\).
According to the problem statement, we can set up an equation:
So, the equation that represents the problem is:
\[6x = 60 - 6\]
Now, we need to solve this linear equation for \(x\).
First, simplify the right side of the equation:
\[60 - 6 = 54\]
So the equation becomes:
\[6x = 54\]
To find the value of \(x\), we need to isolate \(x\) on one side of the equation. Since \(x\) is multiplied by 6, we perform the inverse operation, which is division. We divide both sides of the equation by 6:
\[\frac{6x}{6} = \frac{54}{6}\]
Simplifying both sides gives us:
\[x = 9\]
So, the number is 9.
Let's check if our answer, \(x = 9\), satisfies the original condition:
Since \(54 = 54\), our solution is correct. The number whose 6 times is 6 less than 60 is indeed 9.
Now, let's compare our answer to the given options:
Our calculated number is 9, which matches option D.
The final answer is the number 9.
| Concept | Explanation | How it applies here |
|---|---|---|
| Variable | A symbol (like \(x\)) representing an unknown quantity. | We used \(x\) to represent the unknown number. |
| Equation | A mathematical statement showing two expressions are equal. | \(6x = 60 - 6\) is the equation representing the problem. |
| Solving an Equation | Finding the value(s) of the variable that make the equation true. | We performed steps to find the value of \(x\). |
| Inverse Operations | Operations that undo each other (e.g., multiplication and division). | We used division to undo the multiplication by 6. |
Translating word problems into mathematical equations is a crucial skill in algebra. Here are some common phrases and their mathematical equivalents:
Practicing translating different phrases will help you set up equations correctly and solve word problems efficiently.
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