The set of integers between 11 and 19, inclusive, is: {11, 12, 13, 14, 15, 16, 17, 18, 19}. There are a total of 9 numbers in this set.
The total number of possible pairs that can be formed from 9 distinct numbers is calculated using the combination formula $C(n, 2) = \frac{n(n-1)}{2}$, where $n$ is the number of items.
For $n=9$, the total number of pairs is:
$ C(9, 2) = \frac{9 \times (9-1)}{2} = \frac{9 \times 8}{2} = \frac{72}{2} = 36 $
So, there are 36 possible pairs in total.
Two numbers are coprime if their greatest common divisor (GCD) is 1. We need to find pairs whose GCD is greater than 1 (non-coprime).
Let's list the non-coprime pairs (where GCD > 1) from the set {11, 12, 13, 14, 15, 16, 17, 18, 19}:
Combining and removing duplicates, the unique non-coprime pairs are:
There are 8 non-coprime pairs.
To find the number of coprime pairs, subtract the number of non-coprime pairs from the total number of pairs.
Number of coprime pairs = Total pairs - Non-coprime pairs
Number of coprime pairs = $36 - 8 = 28$.
Consider the following statements :
1. (25)! + 1 is divisible by 26
2. (6)! + 1 is divisible by 7
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