Find the missing term in the given series: 4, 6, 9, 1321, ______ ?
2041
Let's analyze the given number series to find the pattern and determine the missing term.
The series is: \(4, 6, 9, 13\frac{1}{2}, ______\)
First, let's write the mixed fraction as an improper fraction or a decimal to make calculations easier.
So the series can be written as: \(4, 6, 9, 13.5, ______\)
We can look at the difference between consecutive terms or the ratio between them.
The differences (2, 3, 4.5) do not form a simple arithmetic progression. This suggests the pattern might not be based on adding a constant or linearly increasing value.
Let's check the ratio of each term to the previous term.
The ratio between consecutive terms is constant and equal to 1.5 (or \(\frac{3}{2}\)). This indicates that the series follows a geometric progression, where each term is obtained by multiplying the previous term by a constant factor (the common ratio).
The pattern is to multiply the previous term by 1.5 (or \(\frac{3}{2}\)). The last given term is \(13.5\) or \(\frac{27}{2}\).
To find the missing term, we multiply the last term by 1.5:
Missing Term = \(13.5 \times 1.5\)
Calculation:
Alternatively, using fractions:
Missing Term = \(\frac{27}{2} \times \frac{3}{2}\)
Missing Term = \(\frac{27 \times 3}{2 \times 2} = \frac{81}{4}\)
The calculated missing term is 20.25 or \(\frac{81}{4}\). Let's convert \(\frac{81}{4}\) into a mixed fraction to match the options.
\(\frac{81}{4} = 81 \div 4\)
The missing term is \(20\frac{1}{4}\).
Let's compare our result \(20\frac{1}{4}\) with the given options:
Our calculated missing term \(20\frac{1}{4}\) matches Option 2.
Based on the pattern observed (multiplying by 1.5 or \(\frac{3}{2}\)), the missing term in the series \(4, 6, 9, 13\frac{1}{2}, ______\) is \(20\frac{1}{4}\).
| Term Number | Term Value | Calculation from Previous Term |
|---|---|---|
| 1 | 4 | - |
| 2 | 6 | \(4 \times 1.5 = 6\) |
| 3 | 9 | \(6 \times 1.5 = 9\) |
| 4 | \(13\frac{1}{2}\) or 13.5 | \(9 \times 1.5 = 13.5\) |
| 5 | \(20\frac{1}{4}\) or 20.25 | \(13.5 \times 1.5 = 20.25\) |
| Concept | Description | Example Pattern |
|---|---|---|
| Arithmetic Series | Each term is found by adding a constant difference to the previous term. | 2, 5, 8, 11, ... (add 3) |
| Geometric Series | Each term is found by multiplying the previous term by a constant ratio. | 3, 6, 12, 24, ... (multiply by 2) |
| Difference Series | The differences between consecutive terms follow a pattern (e.g., arithmetic, geometric). | 1, 2, 4, 7, 11, ... (differences: 1, 2, 3, 4, ...) |
| Mixed Series | Combinations of different patterns or alternating patterns. | 5, 10, 7, 14, 9, 18, ... (multiply by 2, subtract 3) |
Solving number series problems requires observing the relationship between the terms. Here are some common strategies:
Practice is key to recognizing different types of number series patterns quickly during exams.
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