6A4, 12D7, 20G11, 30J16, ?
This question asks us to identify the pattern in the given sequence and find the missing term. The sequence consists of terms that have three parts: a starting number, a letter, and an ending number. Let's break down the pattern for each part.
Consider the first number in each term:
Let's look at the difference between consecutive numbers:
The difference is increasing by $2$ each time ($6, 8, 10$). The next difference should therefore be $10 + 2 = 12$. So, the next starting number is $30 + 12 = 42$.
Now, let's examine the letter in each term:
Let's find the difference in positions in the alphabet:
The pattern is that each subsequent letter is 3 positions after the previous one in the alphabet. The next letter should be 3 positions after $J$ (the $10^{th}$ letter). This means the $10 + 3 = 13^{th}$ letter.
The $13^{th}$ letter of the alphabet is $M$.
Finally, let's look at the last number in each term:
Let's find the difference between consecutive numbers:
The difference is increasing by $1$ each time ($3, 4, 5$). The next difference should therefore be $5 + 1 = 6$. So, the next ending number is $16 + 6 = 22$.
We found the patterns for each component:
Combining these, the missing term in the sequence is 42M22.