Find the mean proportional between 0.08 and 0.32.
0.16
The mean proportional between two positive numbers, say \(a\) and \(b\), is defined as the square root of their product. It is often represented by \(x\) such that \(a : x :: x : b\), which means \(\frac{a}{x} = \frac{x}{b}\). Cross-multiplying gives \(x^2 = a \times b\). Therefore, \(x = \sqrt{a \times b}\).
In this problem, we need to find the mean proportional between 0.08 and 0.32.
Let \(a = 0.08\) and \(b = 0.32\).
To find the mean proportional, we use the formula:
Mean Proportional \(x = \sqrt{a \times b}\)
Substitute the given values:
\(x = \sqrt{0.08 \times 0.32}\)
First, calculate the product of 0.08 and 0.32:
\(0.08 \times 0.32 = 0.0256\)
Now, find the square root of 0.0256:
\(x = \sqrt{0.0256}\)
To find the square root of 0.0256, we can think of it as \(\sqrt{\frac{256}{10000}}\). The square root of 256 is 16, and the square root of 10000 is 100.
So, \(\sqrt{0.0256} = \frac{16}{100} = 0.16\).
Thus, the mean proportional between 0.08 and 0.32 is 0.16.
The mean proportional 0.16 lies between 0.08 and 0.32. It satisfies the proportion: \(0.08 : 0.16 :: 0.16 : 0.32\). Let's check this:
Since both ratios are equal to \(\frac{1}{2}\), the proportion holds true, confirming that 0.16 is indeed the mean proportional between 0.08 and 0.32.
| Concept | Definition | Formula |
|---|---|---|
| Ratio | A comparison of two quantities by division (e.g., a:b or a/b) | a/b |
| Proportion | An equality of two ratios (e.g., a:b = c:d or a/b = c/d) | a/b = c/d |
| Mean Proportional | A number \(x\) such that \(a:x :: x:b\) where \(a, x, b\) are in continuous proportion | \(x = \sqrt{a \times b}\) |
Ratio and proportion are fundamental concepts in mathematics used to compare quantities and establish relationships between them.
Understanding these concepts helps in solving various problems related to ratios, proportions, scaling, and similarity.
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