Find the length of the direct common tangent to two circles with radii equal to $6$ cm and $18$ cm and the distance between their centers which is equal to $30$ cm.
$6\sqrt{21}$ cm
This solution finds the length of the direct common tangent for two circles using the given radii and distance between centers.
The formula to calculate the length ($L$) of the direct common tangent between two circles is:
$ L = \sqrt{d^2 - (r_2 - r_1)^2} $
Where $d$ is the distance between the centers, and $r_2$ and $r_1$ are the radii of the two circles ($r_2 \ge r_1$).
$ r_2 - r_1 = 18 \text{ cm} - 6 \text{ cm} = 12 \text{ cm} $
$ L = \sqrt{(30 \text{ cm})^2 - (12 \text{ cm})^2} $
$ L = \sqrt{900 \text{ cm}^2 - 144 \text{ cm}^2} $
$ L = \sqrt{756 \text{ cm}^2} $
Factor $756$ to find perfect squares: $756 = 36 \times 21$.
$ L = \sqrt{36 \times 21} \text{ cm} $
$ L = 6\sqrt{21} \text{ cm} $
The length of the direct common tangent is $6\sqrt{21}$ cm.
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