Find the coordinates of the mid−point of the line segment joining the points A(−2, −5) and B(3, −1).
Used Concept:
The midpoint of a line segment with endpoints (x₁, y₁) and (x₂, y₂) is given by the average of the x-coordinates and the y-coordinates.
Midpoint M = [ (x₁ + x₂)/2 , (y₁ + y₂)/2]
Calculation:
Using these coordinates: A(-2, -5) and B(3, -1), the midpoint "M" can be calculated as follows:
Midpoint M = [ (x₁ + x₂)/2 , (y₁ + y₂)/2]
Substituting the given coordinates:
Midpoint M = [(-2 + 3)/2 , (-5 - 1)/2]
After performing the calculations, we obtain:
Midpoint M = [1/2 , -3]
Therefore, the midpoint of the line segment connecting points A(-2, -5) and B(3, -1) is [1/2 , -3].
Important Questions from Sectional Formula
If the point C(1, 1) divides the line segment joining A(-2, 7) and B in the ratio 3 ∶ 2 internally, the coordinates of B are
What is the ratio in which the point \({\rm{C}}\left( { - \frac{2}{7},{\rm{\;}} - \frac{{20}}{7}} \right)\) divides the line joining the points A(-2, -2) and B(2, -4)?
In what ratio does the y-axis divide the line segment joining the points (-3, -4) and (1, 2)?
The line x + y = 4 cuts the line joining P(-1, 1) and Q(5, 7) at R. What is PR ∶ RQ equal to ?
Let \(P\) and \(Q\) be the points on the positive \(x\)-axis and positive \(y\)-axis respectively. A point \(N(2, 1)\) divides the line segment \(PQ\) in the ratio \(1 : 2\). What is the equation of the line?
