Find the coordinates of centroid of ΔABC if the midpoint of BC is D (2,4) and vertex A is (2,-3).
(2,35)
The centroid of a triangle is a very important point. It is the point where the three medians of the triangle intersect. A median is a line segment drawn from a vertex to the midpoint of the opposite side.
A key property of the centroid is that it divides each median in a 2:1 ratio, with the longer segment being towards the vertex.
Let's consider a triangle ABC. Let A be one vertex and D be the midpoint of the opposite side BC. The line segment AD is a median. If G is the centroid of the triangle, then G lies on the median AD such that the distance AG is twice the distance GD. Mathematically, this ratio is expressed as AG : GD = 2 : 1.
Since the centroid G divides the median AD in the ratio 2:1, we can use the section formula to find its coordinates. The section formula helps us find the coordinates of a point that divides a line segment connecting two points in a given ratio.
Let the vertex A be \((x_1, y_1)\) and the midpoint D be \((x_2, y_2)\). The centroid G \((x, y)\) divides the segment AD in the ratio \(m:n = 2:1\).
The section formula for the coordinates of G is:
\(x = \frac{m x_2 + n x_1}{m+n}\)
\(y = \frac{m y_2 + n y_1}{m+n}\)
In this question, we are given:
Now, let's calculate the coordinates of the centroid G \((x, y)\) using the section formula:
\(x = \frac{2(2) + 1(2)}{2+1}\)
\(x = \frac{4 + 2}{3}\)
\(x = \frac{6}{3}\)
\(x = 2\)
\(y = \frac{2(4) + 1(-3)}{2+1}\)
\(y = \frac{8 - 3}{3}\)
\(y = \frac{5}{3}\)
So, the coordinates of the centroid G are \((2, \frac{5}{3})\).
Based on our calculations, the centroid of triangle ABC is located at the point (2, 5/3).
Let's check the given options:
Our calculated coordinates (2, 5/3) match Option 4.
| Given Information | Coordinates |
|---|---|
| Vertex A | (2, -3) |
| Midpoint of BC (D) | (2, 4) |
| Centroid Calculation | Formula | Calculation | Result |
|---|---|---|---|
| x-coordinate | \(\frac{m x_2 + n x_1}{m+n}\) with \(m=2, n=1\) | \(\frac{2(2) + 1(2)}{2+1}\) | 2 |
| y-coordinate | \(\frac{m y_2 + n y_1}{m+n}\) with \(m=2, n=1\) | \(\frac{2(4) + 1(-3)}{2+1}\) | \(\frac{5}{3}\) |
| Concept | Description | Formula/Property |
|---|---|---|
| Centroid | Intersection of medians | Divides median in 2:1 ratio |
| Centroid Coordinates (given vertices \((x_1,y_1), (x_2,y_2), (x_3,y_3)\)) | Average of vertex coordinates | \(G = \left(\frac{x_1+x_2+x_3}{3}, \frac{y_1+y_2+y_3}{3}\right)\) |
| Centroid Coordinates (given vertex A \((x_1,y_1)\) and midpoint D \((x_m,y_m)\) of opposite side) | Using section formula with ratio 2:1 (AD) | \(G = \left(\frac{2x_m + 1x_1}{2+1}, \frac{2y_m + 1y_1}{2+1}\right)\) |
This method using the section formula with a vertex and the midpoint of the opposite side is particularly useful when the coordinates of all three vertices are not directly given, but a vertex and a midpoint are.
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