Find the compound interest on Rs. 8000 at 15% per annum for 2 years (compounded annually.)
Rs. 2580
This problem asks us to find the compound interest on a principal amount when the interest is compounded annually. Let's break down the steps to solve this compound interest problem.
Compound interest is the interest calculated on the initial principal and also on the accumulated interest of previous periods. It's often described as "interest on interest," and it makes a sum grow at a faster rate than simple interest.
From the question, we are given the following details:
To find the compound interest (CI), we first need to calculate the total amount (A) after the given period. The formula for the amount when interest is compounded annually is:
\( A = P \left(1 + \frac{R}{100}\right)^n \)
Where:
Once the amount \( A \) is calculated, the compound interest (CI) is found using the formula:
\( \text{CI} = A - P \)
Let's substitute the given values into the formula for the amount:
\( A = 8000 \left(1 + \frac{15}{100}\right)^2 \)
First, simplify the term inside the bracket:
\( 1 + \frac{15}{100} = 1 + 0.15 = 1.15 \)
Now, substitute this back into the formula for A:
\( A = 8000 (1.15)^2 \)
Calculate \( (1.15)^2 \):
\( (1.15)^2 = 1.15 \times 1.15 = 1.3225 \)
Now, calculate the amount A:
\( A = 8000 \times 1.3225 \)
\( A = 10580 \)
So, the total amount after 2 years is Rs. 10580.
Now, calculate the compound interest (CI):
\( \text{CI} = A - P \)
\( \text{CI} = 10580 - 8000 \)
\( \text{CI} = 2580 \)
Therefore, the compound interest on Rs. 8000 at 15% per annum for 2 years, compounded annually, is Rs. 2580.
| Item | Value |
|---|---|
| Principal (P) | Rs. 8000 |
| Rate (R) | 15% p.a. |
| Time (n) | 2 years |
| Amount (A) | Rs. 10580 |
| Compound Interest (CI) | Rs. 2580 |
Let's compare our calculated compound interest with the given options:
Our calculated compound interest is Rs. 2580, which matches one of the options.
| Term | Definition | Formula (Annual Compounding) |
|---|---|---|
| Principal (P) | The initial amount of money invested or borrowed. | N/A |
| Rate (R) | The percentage at which interest is charged or earned per annum. | N/A |
| Time (n) | The duration for which the money is invested or borrowed. | N/A |
| Amount (A) | The total sum of principal and interest after a certain period. | \( A = P \left(1 + \frac{R}{100}\right)^n \) |
| Compound Interest (CI) | The interest calculated on the principal and accumulated interest from previous periods. | \( \text{CI} = A - P \) or \( \text{CI} = P \left[ \left(1 + \frac{R}{100}\right)^n - 1 \right] \) |
It is helpful to understand the difference between compound interest and simple interest.
In this problem, if it were simple interest, the calculation would be:
\( \text{SI} = \frac{8000 \times 15 \times 2}{100} = \frac{240000}{100} = 2400 \)
The simple interest would be Rs. 2400, which is less than the compound interest (Rs. 2580), illustrating how compounding earns more over time.
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