Question
Find the area of a triangle, whose sides are 0.24 m, 28 cm, and 32 cm.
The correct answer is
84 √15 cm²
Step 1
\(a=24\text{ cm},\quad s=\frac{24+28+32}2=42\text{ cm}\)
Step 2
\(A=\sqrt{42(18)(14)(10)}=84\sqrt{15}\text{ cm}^2\)
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Important Questions from Mensuration
- The volume of a wall that is 5 times as high as it is broad and 8 times as long as it is high is 12.8 cubic meters. Find the breadth of the wall.
- If the radius of a sphere is increased by 2 cm, then its surface area increases by 704 cm\(^2\). Using \(\pi = \frac{22}{7}\), find the radius of the sphere after the increase.
- What is the perimeter of an equilateral triangle with side 13 cm?
- The perimeter of a square is 76 m. Its area (in $m^2$) is:
- A cylindrical rod has an outer curved surface area of 1800 cm$^2$. If the length of the rod is 52 cm, then the outer radius (in cm) of the rod, correct to two places of decimal, is:
Take $\pi = \frac{22}{7}$
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