Find the area of a triangle, whose sides are 0.24 m, 28 cm, and 32 cm.
84 √15 cm²
To find the area of a triangle with sides 0.24 m, 28 cm, and 32 cm, we first need to convert all measurements to a consistent unit. Let's convert the 0.24 m to centimeters: 0.24 m = 24 cm. The sides now are 24 cm, 28 cm, and 32 cm. We use Heron's formula to find the area of the triangle.
Heron's formula states that the area of a triangle with sides a, b, and c is given by:
Area = √(s × (s - a) × (s - b) × (s - c))
where s is the semi-perimeter of the triangle:
s = (a + b + c) / 2
Inserting our values:
s = (24 + 28 + 32) / 2 = 42
Now, apply Heron's formula:
Area = √(42 × (42 - 24) × (42 - 28) × (42 - 32))
Calculate the terms:
Substitute these back into the formula:
Area = √(42 × 18 × 14 × 10)
Calculating inside the square root gives:
Finally, calculate the square root:
Area = √105840
We recognize that the expression can be rewritten to include a perfect square:
Area = √(15 × 7056)
Since √7056 = 84, we get:
Area = 84√15 cm²
Thus, the area of the triangle is 84√15 cm², which corresponds to the correct answer 84√15 cm².
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