The question requires us to analyze the number $8731245$. The main goal is to determine how many digits hold their original positions after the digits of the number are rearranged in ascending order from left to right.
The starting number is $8731245$. Let's identify each digit and its corresponding position:
Next, we take all the digits from the original number {$8$, $7$, $3$, $1$, $2$, $4$, $5$} and arrange them in ascending order (from smallest to largest).
The sequence of digits sorted in ascending order is {$1$, $2$, $3$, $4$, $5$, $7$, $8$}.
To find out which digits remain in their original places, we compare the original number's digits with the sorted number's digits position by position. A table helps visualize this comparison:
| Original Digit | Original Position | Sorted Digit | Sorted Position | Position Unchanged? |
|---|---|---|---|---|
| $8$ | $1^{st}$ | $1$ | $1^{st}$ | No |
| $7$ | $2^{nd}$ | $2$ | $2^{nd}$ | No |
| $3$ | $3^{rd}$ | $3$ | $3^{rd}$ | Yes |
| $1$ | $4^{th}$ | $4$ | $4^{th}$ | No |
| $2$ | $5^{th}$ | $5$ | $5^{th}$ | No |
| $4$ | $6^{th}$ | $7$ | $6^{th}$ | No |
| $5$ | $7^{th}$ | $8$ | $7^{th}$ | No |
We carefully examine the table and the comparison:
From this step-by-step comparison, we find that only the digit $3$ remains in its original position, which is the 3rd position.
Therefore, the total count of digits whose positions do not change after arranging the number's digits in ascending order is one.