Each of the digits in the number 8642571 is arranged in ascending order from left to right. What will be the sum of the digits which are fourth from the left and second from the right in the new number thus formed?
This problem involves rearranging the digits of a given number and then finding the sum of specific digits in the new arrangement.
The original number is 8642571. The digits present in this number are:
We need to arrange these digits from smallest to largest (ascending order). Let's list them:
The digits are: 1, 2, 4, 5, 6, 7, 8.
The new number formed by arranging these digits in ascending order is 1245678.
| Original Digits | 1, 2, 4, 5, 6, 7, 8 |
| New Number (Ascending Order) | 1245678 |
Now, we need to find two specific digits in the new number (1245678):
The final step is to find the sum of the two identified digits (5 and 7).
Using LaTeX for the calculation:
$\text{Sum} = (\text{Fourth digit from left}) + (\text{Second digit from right})$
$\text{Sum} = 5 + 7$
$\text{Sum} = 12$
Therefore, the sum of the digit fourth from the left and the digit second from the right in the newly formed number is 12.
Refer to the following letter, number, symbol series and answer the question that follows.
(Left) C H * * 8 5 9 * 4 9 1 6 5 L # 5 6 5 £ * K B (Right)
If all the numbers are dropped from the series, which of the following will be fifth from the left?
Refer to the following letter, number and symbol series and answer the question that follows. Counting to be done from left to right only. (All numbers are single-digit numbers only.)
(Left) N R B C & 1 J 5 ! $ 7 S K 9 3 # (Right)
How many such numbers are there which are immediately preceded by a symbol and also immediately followed by a letter?