During normal working of transistor as amplifier, the emitter junction is _______.
Forward biased
For a transistor to function correctly as an amplifier, it needs to be biased into a specific operating mode known as the active region.
A bipolar junction transistor (BJT) has two p-n junctions:
The way these two junctions are biased (either forward biased or reverse biased) determines how the transistor operates.
There are generally three main operating regions for a transistor:
When a transistor is biased in the active region, a small change in the input signal at the base (or emitter) can control a much larger current flowing between the collector and emitter. This controlled current allows the transistor to amplify signals.
The table below summarizes the biasing conditions for the different operating regions:
| Operating Region | Emitter-Base Junction | Collector-Base Junction | Typical Application |
|---|---|---|---|
| Cut-off | Reverse Biased | Reverse Biased | Switch (OFF state) |
| Saturation | Forward Biased | Forward Biased | Switch (ON state) |
| Active | Forward Biased | Reverse Biased | Amplifier |
Therefore, for a transistor to operate normally as an amplifier, the emitter junction must be forward biased.
BC147 is the transistor used for:
Which of the following is NOT true for a common collector transistor?
The other name for the common collector amplifier is -
Match List I with List II:
List I (Bias Configuration of BJT) | List II (Stability factor equation) | ||
| (A) | Fixed Bias Configuration | (I) | S(V BE ) = \(\rm −\frac{\beta/R_E}{\beta+R_{TH}/R_E}\) |
| (B) | Emitter Bias Configuration | (II) | S(V BE ) = −β/R E |
| (C) | Voltage Divider Configuration | (III) | S(V BE ) = \(\rm −\frac{\beta/R_C}{\beta+R_E/R_C}\) |
| (D) | Feedback Bias Configuration | (IV) | S(V BE ) = \(\rm −\frac{\beta/R_E}{\beta+R_B/R_E}\) |
Choose the correct answer from the options given below :