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Question

Dimensional formula of Stefan Boltzmann constant

The correct answer is

M1L0T-3K-4

Stefan-Boltzmann Constant: Deriving the Dimensional Formula

The Stefan-Boltzmann constant, denoted by the symbol $\sigma$ (sigma), is a physical constant that relates the total energy radiated per unit surface area of a black body across all wavelengths per unit time to the fourth power of its absolute temperature. This relationship is described by the Stefan-Boltzmann Law.

The Stefan-Boltzmann Law can be expressed as:

$\qquad I = \sigma T^4$

Where:

  • $I$ is the emissive power (or intensity), which is the total energy radiated per unit surface area per unit time.
  • $\sigma$ is the Stefan-Boltzmann constant.
  • $T$ is the absolute temperature of the black body in Kelvin.

To find the dimensional formula of the Stefan-Boltzmann constant ($\sigma$), we can rearrange the equation:

$\qquad \sigma = \frac{I}{T^4}$

Dimensional Analysis of Emissive Power (I)

First, let's determine the dimensional formula for emissive power ($I$). Emissive power is defined as energy per unit area per unit time. Therefore, its formula is:

$\qquad I = \frac{\text{Energy}}{\text{Area} \times \text{Time}}$

Now, let's find the dimensions of each component:

  • Energy (E): Energy has the dimensions of work, which is Force × Displacement. Force has dimensions of Mass × Acceleration ($[\text{M L T}^{-2}]$). So, the dimension of energy is $[\text{M L T}^{-2}] \times [\text{L}] = [\text{M L}^2 \text{T}^{-2}]$.
  • Area (A): Area is a measure of two-dimensional space, so its dimension is $[\text{L}^2]$.
  • Time (t): Time is a fundamental dimension, so its dimension is $[\text{T}]$.

Substituting these dimensions into the formula for $I$:

$\qquad [I] = \frac{[\text{M L}^2 \text{T}^{-2}]}{[\text{L}^2] \times [\text{T}]}$

$\qquad [I] = [\text{M L}^{(2-2)} \text{T}^{(-2-1)}]$

$\qquad [I] = [\text{M L}^0 \text{T}^{-3}]$

Dimensional Analysis of Temperature (T)

Temperature ($T$) is a fundamental quantity in the International System of Units (SI) and its dimension is represented by Kelvin (K).

$\qquad [\text{T}] = [\text{K}]$

Therefore, the dimension of $T^4$ is $[\text{K}^4]$.

Calculating the Dimensional Formula of Stefan-Boltzmann Constant ($\sigma$)

Now, we can substitute the dimensions of $I$ and $T^4$ back into the equation for $\sigma$:

$\qquad [\sigma] = \frac{[I]}{[T^4]}$

$\qquad [\sigma] = \frac{[\text{M L}^0 \text{T}^{-3}]}{[\text{K}^4]}$

$\qquad [\sigma] = [\text{M}^1 \text{L}^0 \text{T}^{-3} \text{K}^{-4}]$

Thus, the dimensional formula of the Stefan-Boltzmann constant is $\text{M}^1 \text{L}^0 \text{T}^{-3} \text{K}^{-4}$.

Comparing this with the given options:

Option Dimensional Formula
1 M1L0T-3K-4
2 M1L3T-3K-4
3 M-2L2T-3K-4
4 M-1L0T-3K-4

The calculated dimensional formula matches option 1.

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Important Questions from Laws of Radiation

  1. Two spherical balls of same material and surface finish have their diameters in the ratio of 2 : 1. Both are heated to same temperature and allowed to cool by radiation. Rate of cooling of big ball as compared to smaller one will be in the ratio of

  2. Sun’s surface at 5800 K emits radiation at a wavelength of 0.5 μA. A furnace at 300°C will emit through a small opening, radiation at a wavelength of

  3. Which of the following substance has highest thermal diffusivity at room temperature?

  4. The rate at which is energy is radiated by a black body at an absolute temperature is given by ______.

  5. The spectral emissive power E1 for a diffusely emitting surface is E1 = 0 for λ < 3 μm; E1 = 150 W/m2-μm for 3 < λ < 12 μm; E1 = 300 W/m2-μm for 12 < λ < 25 μm; E1 = 0 for λ > 25 μm. The total emissive power of the surface over the entire spectrum is

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