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Question

Dimensional formula of Stefan Boltzmann constant

The correct answer is

M1L0T-3K-4

Stefan-Boltzmann Constant: Deriving the Dimensional Formula

The Stefan-Boltzmann constant, denoted by the symbol $\sigma$ (sigma), is a physical constant that relates the total energy radiated per unit surface area of a black body across all wavelengths per unit time to the fourth power of its absolute temperature. This relationship is described by the Stefan-Boltzmann Law.

The Stefan-Boltzmann Law can be expressed as:

$\qquad I = \sigma T^4$

Where:

  • $I$ is the emissive power (or intensity), which is the total energy radiated per unit surface area per unit time.
  • $\sigma$ is the Stefan-Boltzmann constant.
  • $T$ is the absolute temperature of the black body in Kelvin.

To find the dimensional formula of the Stefan-Boltzmann constant ($\sigma$), we can rearrange the equation:

$\qquad \sigma = \frac{I}{T^4}$

Dimensional Analysis of Emissive Power (I)

First, let's determine the dimensional formula for emissive power ($I$). Emissive power is defined as energy per unit area per unit time. Therefore, its formula is:

$\qquad I = \frac{\text{Energy}}{\text{Area} \times \text{Time}}$

Now, let's find the dimensions of each component:

  • Energy (E): Energy has the dimensions of work, which is Force × Displacement. Force has dimensions of Mass × Acceleration ($[\text{M L T}^{-2}]$). So, the dimension of energy is $[\text{M L T}^{-2}] \times [\text{L}] = [\text{M L}^2 \text{T}^{-2}]$.
  • Area (A): Area is a measure of two-dimensional space, so its dimension is $[\text{L}^2]$.
  • Time (t): Time is a fundamental dimension, so its dimension is $[\text{T}]$.

Substituting these dimensions into the formula for $I$:

$\qquad [I] = \frac{[\text{M L}^2 \text{T}^{-2}]}{[\text{L}^2] \times [\text{T}]}$

$\qquad [I] = [\text{M L}^{(2-2)} \text{T}^{(-2-1)}]$

$\qquad [I] = [\text{M L}^0 \text{T}^{-3}]$

Dimensional Analysis of Temperature (T)

Temperature ($T$) is a fundamental quantity in the International System of Units (SI) and its dimension is represented by Kelvin (K).

$\qquad [\text{T}] = [\text{K}]$

Therefore, the dimension of $T^4$ is $[\text{K}^4]$.

Calculating the Dimensional Formula of Stefan-Boltzmann Constant ($\sigma$)

Now, we can substitute the dimensions of $I$ and $T^4$ back into the equation for $\sigma$:

$\qquad [\sigma] = \frac{[I]}{[T^4]}$

$\qquad [\sigma] = \frac{[\text{M L}^0 \text{T}^{-3}]}{[\text{K}^4]}$

$\qquad [\sigma] = [\text{M}^1 \text{L}^0 \text{T}^{-3} \text{K}^{-4}]$

Thus, the dimensional formula of the Stefan-Boltzmann constant is $\text{M}^1 \text{L}^0 \text{T}^{-3} \text{K}^{-4}$.

Comparing this with the given options:

Option Dimensional Formula
1 M1L0T-3K-4
2 M1L3T-3K-4
3 M-2L2T-3K-4
4 M-1L0T-3K-4

The calculated dimensional formula matches option 1.

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Important Questions from Laws of Radiation

  1. Newton’s Law of cooling is an approximate form of

  2. _______ states that the emissivity of a body is equal to its absorptivity when the body remains in thermal equilibrium with its surroundings.
  3. The rate at which is energy is radiated by a black body at an absolute temperature is given by ______.

  4. Consider black body radiation in thermal equilibrium contained in a two-dimensional box. The dependence of the energy density on the temperature T is

  5. The heat transfer equation Q = σAT 4is called

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