Dimensional formula of Stefan Boltzmann constant
M1L0T-3K-4
The Stefan-Boltzmann constant, denoted by the symbol $\sigma$ (sigma), is a physical constant that relates the total energy radiated per unit surface area of a black body across all wavelengths per unit time to the fourth power of its absolute temperature. This relationship is described by the Stefan-Boltzmann Law.
The Stefan-Boltzmann Law can be expressed as:
$\qquad I = \sigma T^4$
Where:
To find the dimensional formula of the Stefan-Boltzmann constant ($\sigma$), we can rearrange the equation:
$\qquad \sigma = \frac{I}{T^4}$
First, let's determine the dimensional formula for emissive power ($I$). Emissive power is defined as energy per unit area per unit time. Therefore, its formula is:
$\qquad I = \frac{\text{Energy}}{\text{Area} \times \text{Time}}$
Now, let's find the dimensions of each component:
Substituting these dimensions into the formula for $I$:
$\qquad [I] = \frac{[\text{M L}^2 \text{T}^{-2}]}{[\text{L}^2] \times [\text{T}]}$
$\qquad [I] = [\text{M L}^{(2-2)} \text{T}^{(-2-1)}]$
$\qquad [I] = [\text{M L}^0 \text{T}^{-3}]$
Temperature ($T$) is a fundamental quantity in the International System of Units (SI) and its dimension is represented by Kelvin (K).
$\qquad [\text{T}] = [\text{K}]$
Therefore, the dimension of $T^4$ is $[\text{K}^4]$.
Now, we can substitute the dimensions of $I$ and $T^4$ back into the equation for $\sigma$:
$\qquad [\sigma] = \frac{[I]}{[T^4]}$
$\qquad [\sigma] = \frac{[\text{M L}^0 \text{T}^{-3}]}{[\text{K}^4]}$
$\qquad [\sigma] = [\text{M}^1 \text{L}^0 \text{T}^{-3} \text{K}^{-4}]$
Thus, the dimensional formula of the Stefan-Boltzmann constant is $\text{M}^1 \text{L}^0 \text{T}^{-3} \text{K}^{-4}$.
Comparing this with the given options:
| Option | Dimensional Formula |
|---|---|
| 1 | M1L0T-3K-4 |
| 2 | M1L3T-3K-4 |
| 3 | M-2L2T-3K-4 |
| 4 | M-1L0T-3K-4 |
The calculated dimensional formula matches option 1.
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