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Question

Determine the resonant frequency of an IMPATT diode having the following specifications:

Carrier drift velocity: 2 × 107 cm/s

Drift-region length: 5 μm

Maximum operating voltage: 100 V

Maximum operating current: 250 mA

Efficiency: 20%

Breakdown voltage: 90 V

The correct answer is

20 GHz

IMPATT Diode and its Resonant Frequency

An IMPATT (Impact Ionization Avalanche Transit-Time) diode is a specialized type of semiconductor diode designed for generating microwave power. It operates based on the principle of impact ionization, where carriers multiply rapidly, and the transit-time effect, where these carriers drift across a specific region of the diode. The ability of an IMPATT diode to produce high-frequency oscillations makes its resonant frequency a very important parameter. Understanding and determining the resonant frequency is crucial for its application in various microwave and millimeter-wave circuits.

Resonant Frequency Calculation for IMPATT Diode

The resonant frequency ($f_r$) of an IMPATT diode is primarily determined by the carrier drift velocity ($v_d$) and the length of its drift region ($L$). These two physical parameters directly influence how quickly charge carriers can traverse the diode, which in turn dictates the frequency at which the diode resonates most efficiently. The fundamental formula used to calculate the resonant frequency for an IMPATT diode is given as:

$f_r = \frac{v_d}{2L}$

Where:

  • $v_d$ represents the carrier drift velocity, typically measured in meters per second (m/s).
  • $L$ denotes the effective drift-region length, measured in meters (m).

Parameters for Resonant Frequency Determination

Before proceeding with the calculation, it is essential to ensure that all given parameters are in consistent units, preferably the International System of Units (SI). Let's convert the provided specifications into SI units:

Parameter Given Value Converted SI Value
Carrier drift velocity ($v_d$) $2 \times 10^7$ cm/s $2 \times 10^7 \times 10^{-2}$ m/s = $2 \times 10^5$ m/s
Drift-region length ($L$) $5 \mu$m $5 \times 10^{-6}$ m

It is important to note that other specifications provided, such as Maximum operating voltage, Maximum operating current, Efficiency, and Breakdown voltage, are vital for understanding the overall performance characteristics and safe operating limits of the IMPATT diode. However, they are not directly used in the calculation of the fundamental resonant frequency based on the provided formula and typical IMPATT diode theory.

Calculating IMPATT Diode Resonant Frequency

Now, we will substitute the converted values of the carrier drift velocity ($v_d$) and the drift-region length ($L$) into the resonant frequency formula to determine the resonant frequency of the IMPATT diode:

The formula is:

$f_r = \frac{v_d}{2L}$

Substitute the values:

$f_r = \frac{2 \times 10^5 \text{ m/s}}{2 \times (5 \times 10^{-6} \text{ m})}$

First, calculate the denominator:

$2 \times (5 \times 10^{-6} \text{ m}) = 10 \times 10^{-6} \text{ m} = 1 \times 10^{-5} \text{ m}$

Now, substitute this back into the frequency formula:

$f_r = \frac{2 \times 10^5 \text{ m/s}}{1 \times 10^{-5} \text{ m}}$

Perform the division:

$f_r = 2 \times 10^{5 - (-5)} \text{ Hz}$

$f_r = 2 \times 10^{10} \text{ Hz}$

To express this frequency in Gigahertz (GHz), we recall that 1 GHz = $10^9$ Hz:

$f_r = \frac{2 \times 10^{10}}{10^9} \text{ GHz}$

$f_r = 20 \text{ GHz}$

Determined Resonant Frequency

Based on the provided specifications and the standard formula for an IMPATT diode, the calculated resonant frequency of the diode is 20 GHz. This frequency value indicates the optimal operating frequency for microwave power generation by this specific IMPATT diode.

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Important Questions from Diodes and Its Applications

  1. Which of the following statements is FALSE about LED lamps?

  2. A Zener diode is used in _______ for voltage regulation.

  3. Which of the following diodes can be used as Voltage Regulator if used in reverse bias?

  4. What is it called when a diode exceeds the reverse voltage and then it fails and passes more current in the reverse direction?

  5. Select the option that is true regarding the following two statements labeled Assertion (A) and Reason (R).

    Assertion (A): Whenever we measure an electrical signal, there are chances of over current which leads to overheating of the meter. In such cases, the meter can be protected by using a semiconductor diode of suitable rating.

    Reason (R): As soon as the diode is short-circuited, the meter current is diverted through the diode.

    As a result, the meter is being protected from excess heating.

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