Determine the power dissipated (in W) by the 6 ohms resistor in the circuit given below.
To determine the power dissipated by the 6 ohms resistor, we first need to analyze the circuit. The circuit has two current sources: 2A and 6A. These two sources are connected in different branches of the circuit.
Let's analyze the circuit:
- The 2A current source flows through the 3 ohms resistor.
- The 6A current source flows through the 1 ohm resistor.
- Both sources are equal and opposite regarding the 6 ohms resistor. Thus, they do not contribute to any current through this resistor.
To calculate the power dissipated across the 6 ohms resistor, we use the formula:
\(P = I^2 \times R\), where \(I\) is the current through the resistor and \(R\) is the resistance.
Since no current flows through the 6 ohms resistor due to the balancing effect of the two current sources, the current \(I = 0 \, \text{A}\).
Thus, the power dissipated is:
\(P = 0^2 \times 6 = 0 \, \text{W}\).
Therefore, the correct answer is 0 W.
Important Questions from Kirchhoff's Laws
Kirchhoff's current law is based on the conservation of
Kirchhoff's law will fail in case of -
The dual pair of the node and open circuit are ____________
In case of circuit laws, the currents flowing in various conductors in an electrical circuit are calculated by applying ________.
According to Kirchhoff Voltage Law, the algebric sum of all voltage drop and e.m.f. in any closed circuit in a network is equal to -
